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nata0808 [166]
2 years ago
14

a disk initially at rest rotates with constant angular acceleration through an angel of 50 rad in 5 sec find the angular speed o

f the disk just after 3 sec. please step by step
Physics
1 answer:
lisov135 [29]2 years ago
3 0

Recall the formula,

∆<em>θ</em> = <em>ω</em>₀ <em>t</em> + 1/2 <em>α</em> <em>t</em> ²

where ∆<em>θ</em> = angular displacement, <em>ω</em>₀ = initial angular speed (which is zero because the disk starts at rest), <em>α</em> = angular acceleration, and <em>t</em> = time. Solve for the acceleration with the given information:

50 rad = 1/2 <em>α</em> (5 s)²

<em>α</em> = (100 rad) / (25 s²)

<em>α</em> = 4 rad/s²

Now find the angular speed <em>ω </em>after 3 s using the formula,

<em>ω</em> = <em>ω</em>₀ + <em>α</em> <em>t</em>

<em>ω</em> = (4 rad/s²) (3 s)

<em>ω</em> = 12 rad/s

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<em>B) 1.0 × 10^5 V</em>

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We must compute the total electric potential in the center of the square. We need to know the distance from all the corners to the center. The diagonal of the square is

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\displaystyle r=\frac{1}{\sqrt{2}}=0.707\ m

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V_t=V_1+V_2+V_3+V_4

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\displaystyle V_1=V_2=k\frac{Q}{r}=9\times 10^9 \frac{4\times 10^{-6}}{0.707}

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The total potential is

V_t=50912\ V+50912\ V=1\times 10^5\ V

\boxed{V_t=1\times 10^5\ V}

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3 years ago
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Explanation:

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2 years ago
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