V=IR, therefore when resistance is constant the voltage and current are directly proportional
Answer:
F = 0N
Explanation:
The force between two charges is given by

where r is the distance between the charges and K is the Coulomb's constant
(k=8-89*10^9Nm^2/C^2)
The force in the first charge is only the sum of the forces due to the other charges. Hence we have


Ft=0N
Hope this helps!!
Answer:
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