Answer:
l guess c is the answer
Explanation:
it is true because in oxygen does not share any atoms with hydrogen
Answer:
220
Explanation:
V₀= Vmax(D)/ (D) + km
0.66/100=vmax(130km)/(130km)+(km)
Vmax= 0.66×131/130×1000 =0.6650mm/d
kwat= vmax/ET
=0.665×10⁻³/ 3×10⁻⁶
= 0.22×10³
= 220
Some of the NH₄+ will combine with the OH- and shift the equilibrium backwards and from NH₄OH to balance the change produced by addition of NH₄+ ions.
The volume of HCOOH is 0.003 Lt and the volume of HCOONa is 0.017 LT.
Explanation:
For acidic buffer
PH = Pka + log
4.25 = 3.75 + log
log = 0.75
log = 5.62 is considered as equation 1.
Let V₁ ml of HCOOH and V₂ml of HCOONA was mixed and the final volume is 100 ml .
V₁ *0.5 + V₂ *0.5 =0.1 * 100
V₁+V₂ = = 20 is the second equation.
Now concentration of salt and acid are
V₂ [salt] = 0.5/100 and v₁ [acid] = 0.5/100
by substituting these in equation 1 we get,
= 5.62
V₂ = V₁ * 5.62 is the 3 rd equation
by solving 2 and 3 we get,
5.62 V₁ + V₁ = 20
= 6.62 V₁ = 20
V₁ = 3.02 ml
V₁ = 0.003 LT
V₂ = V₁ * 5.62
V₂ = 0.017 LT
Hence the volume of HCOOH is 0.003 Lt and the volume of HCOONa is 0.017 LT.