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BaLLatris [955]
4 years ago
10

2^(2x)+2^(x+2)−12=0 | Solve for x Answer

Mathematics
1 answer:
Stolb23 [73]4 years ago
3 0
2^(2x) = (2^x)^2 ;
2^(x+2) = (2^x) × 4 ;
Let be 2^x = y > 0 ;
y^2 + 4y - 12 = 0 ;
a = 1 ;
b = 4 ;
c = - 12 ;
b^2 - 4ac = 16 + 48 = 64 ;
y1 = ( - 4 + 8 ) / 2 = 2 > 0 ( correct ) ;
y2 = ( - 4 - 8 ) / 2 = - 6 > 0 ( false ) ;
Then, 2^x = 2 ;
x = 1.
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The expected values of the binomial distribution are given as follows:

1. 214.

2. 21.

3. 31.

<h3>What is the binomial probability distribution?</h3>

It is the <u>probability of exactly x successes on n repeated trials, with p probability</u> of a success on each trial.

The expected value of the binomial distribution is:

E(X) = np

For item 1, the parameters are:

p = 3/7, n = 500.

Hence the expected value is:

E(X) = np = 500 x 3/7 = 1500/7 = 214.

For item 2, the parameters are:

p = 0.083, n = 250.

Hence the expected value is:

E(X) = np = 250 x 0.083 = 21.

For item 3, the parameters are:

p = 1/13, n = 400.

Hence the expected value is:

E(X) = np = 400 x 1/13 = 31.

More can be learned about the binomial distribution at brainly.com/question/24863377

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