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Mrrafil [7]
3 years ago
12

There are competitions in which pilots fly small planes low over the ground and drop weights, trying to hit a target. A pilot fl

ying low and slow drops a weight; it takes 2.0 s to hit the ground, during which it travels a horizontal distance of 100 m. Now the pilot does a run at the same height but twice the speed. How much time does it take the weight to hit the ground? How far does it travel before it lands?
Physics
2 answers:
Gnom [1K]3 years ago
8 0

Answer:

1) 2 seconds

2) 200 m

Explanation:

1) Fall time at initial speed s_{1} = t_{1}

  Fall time at final speed s_{2} = t_{2}

  Initial fall height h_{1} at initial speed = Final fall height h_{2} at final speed i.e h_{1} = h_{2}

s = speed

t = time

h = height

Therefore, since fall time depends on fall height where acceleration due to gravity (g) is constant,

Fall time at s_{1} = Fall time at s_{2}

i.e t_{1} = t_{2} = <u>2.0 s</u>

<u>Time taken to land = 2.0 s</u>

2) Initial distance traveled (S_{1}) at initial speed s_{1} = 100 m

   Final speed s_{2} is double initial speed i.e s_{2} = 2s_{1}

Therefore, since distance traveled is directly proportional to speed,

Final distance traveled S_{2} at final speed s_{2} is double initial distance S_{1}

i.e S_{2} = 2S_{1}

    2S_{1} = 2 x 100 m = <u>200 m</u>

<u>Distance traveled = 200 m</u>

sattari [20]3 years ago
5 0

Answer:

2.0 s, 200 m

Explanation:

Time to hit the ground depends only on height.  Since the plane is at the same height, the weight lands at the same time as before, 2.0 s.

Since the plane is going twice as fast, the weight will travel twice as far (ignoring air resistance).  So it will travel a horizontal distance of 200 m.

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