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Harrizon [31]
4 years ago
12

What determines how many items make up a particular unit

Chemistry
2 answers:
Ierofanga [76]4 years ago
3 0
The Avogadro's number determines how many items make up a particular unit, such that 1 mole of a substance contains 6.022 × 10^23 items.
These items may be particles such as molecules, atoms, ions , etc
Therefore, 1 mole of anything has 6.022×10^23 items.
This number is called the Avogadro's constant and applies to all substances, and is normally used by researchers and scientists to determine the number of moles of elements and compounds.
mel-nik [20]4 years ago
3 0

Answer:

Avogadro's number determines how many elements make up a particular unit.

Explanation:

According to the International System, the mole is defined as the amount of substance that contains as many entities (atoms, molecules, ions, electrons or other entities) as the number of atoms in 0.012 kg of pure carbon-12. According to this definition, the parameters are in their lowest state of energy, at rest and without interacting with others.

On the other hand, the Avogadro Number or Avogadro Constant is called the number of particles that have a substance (usually atoms or molecules) and that can be found in the amount of one mole of that substance. So Avogadro's number represents the amount of atoms in 0.012 kg of carbon 12. Its value is 6.023 * 1023 particles per mole. Avogadro's number represents a quantity without an associated physical dimension, so it is considered a pure number that allows describing a physical characteristic without dimension or explicit unit of expression. Avogadro's number applies to any substance.

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kumpel [21]

Answer:

D

Explanation:

A is length

B is Reflection

C Mass

D is Density

A B can be eliminated immediately and you will learn the rest in school

Hope it helps!! :)

3 0
3 years ago
Which type of bond is found in many carbon-to-carbon bonds in canola oil, but very few carbon-to-carbon bonds in butter? a.)C–C
PtichkaEL [24]
B.)C=C is the right answer.
because h<span>aving more double bonds than single bonds decreases the melting point and, hence, the fluidity of the substance this is why butter is a solid but canola oil is a liquid at room temperature.</span>
8 0
4 years ago
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A student performs the following experiment.
dybincka [34]

Answer:

Two different changes have occurred in the beaker. The description of the step 1 suggests that most likely a <u>chemical change</u> has occured while the description of the step 2 correspond to a<u> physical change</u>.

Explanation:

When the mixture of two liquid colorless substances results in the appearance of solid particles you first thing in the appareance of a new substance. If this is the case, it means that the original substances reacted chemically to form a new product, so this is a chemical change.

On the other hand, the second step describes just a physical change as it has been just that the yellow particles settled and then a physical separation by <em>decantation</em>. Decantation does not change the chemical properties of the particles settled, they are jsut separeated from the liquid. During this step both the yellow particles and the liquid in the beaker keep their chemical properties, so this is just a physical change.

4 0
3 years ago
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Can any of you unscramble the word mmncotiuy
Elden [556K]
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7 0
3 years ago
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Please help I’m timed !!!
Rashid [163]

Answer:

b. \% diss =4.4x10^{-2}\%

Explanation:

Hello there!

In this case, given the ionization reaction of HClO as weak acid:

HClO\rightleftharpoons H^++ClO^-

We can write the equilibrium expression as shown below:

Ka=3.5x10^{-8}=\frac{[H^+][ClO^-]}{[HClO]}

In such a way, via the definition of x as the reaction extent, we can write:

3.5x10^{-8}=\frac{x^2}{[HClO]}

As long as Ka<<<<1 so that the x on the bottom can be neglected. Thus, we solve for x as shown below:

x=\sqrt{3.5x10^{-8}*0.18} =\\\\x=7.94x10^{-5}M

And finally the percent dissociation:

\% diss=\frac{x}{[HClO]} *100\%\\\\\% diss=\frac{7.94x10^{-5}M}{0.18}*100\% \\\\\% diss =0.044\%=4.4x10^{-2}\%

Which is choice b.

Best regards!

6 0
3 years ago
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