Answer:
D
Explanation:
A is length
B is Reflection
C Mass
D is Density
A B can be eliminated immediately and you will learn the rest in school
Hope it helps!! :)
B.)C=C is the right answer.
because h<span>aving more double bonds than single bonds decreases the melting point and, hence, the fluidity of the substance this is why butter is a solid but canola oil is a liquid at room temperature.</span>
Answer:
Two different changes have occurred in the beaker. The description of the step 1 suggests that most likely a <u>chemical change</u> has occured while the description of the step 2 correspond to a<u> physical change</u>.
Explanation:
When the mixture of two liquid colorless substances results in the appearance of solid particles you first thing in the appareance of a new substance. If this is the case, it means that the original substances reacted chemically to form a new product, so this is a chemical change.
On the other hand, the second step describes just a physical change as it has been just that the yellow particles settled and then a physical separation by <em>decantation</em>. Decantation does not change the chemical properties of the particles settled, they are jsut separeated from the liquid. During this step both the yellow particles and the liquid in the beaker keep their chemical properties, so this is just a physical change.
Mmncotiuy unscrambled would be Community
Answer:
b. 
Explanation:
Hello there!
In this case, given the ionization reaction of HClO as weak acid:

We can write the equilibrium expression as shown below:
![Ka=3.5x10^{-8}=\frac{[H^+][ClO^-]}{[HClO]}](https://tex.z-dn.net/?f=Ka%3D3.5x10%5E%7B-8%7D%3D%5Cfrac%7B%5BH%5E%2B%5D%5BClO%5E-%5D%7D%7B%5BHClO%5D%7D)
In such a way, via the definition of x as the reaction extent, we can write:
![3.5x10^{-8}=\frac{x^2}{[HClO]}](https://tex.z-dn.net/?f=3.5x10%5E%7B-8%7D%3D%5Cfrac%7Bx%5E2%7D%7B%5BHClO%5D%7D)
As long as Ka<<<<1 so that the x on the bottom can be neglected. Thus, we solve for x as shown below:

And finally the percent dissociation:
![\% diss=\frac{x}{[HClO]} *100\%\\\\\% diss=\frac{7.94x10^{-5}M}{0.18}*100\% \\\\\% diss =0.044\%=4.4x10^{-2}\%](https://tex.z-dn.net/?f=%5C%25%20diss%3D%5Cfrac%7Bx%7D%7B%5BHClO%5D%7D%20%2A100%5C%25%5C%5C%5C%5C%5C%25%20diss%3D%5Cfrac%7B7.94x10%5E%7B-5%7DM%7D%7B0.18%7D%2A100%5C%25%20%5C%5C%5C%5C%5C%25%20diss%20%3D0.044%5C%25%3D4.4x10%5E%7B-2%7D%5C%25)
Which is choice b.
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