Answer:
v = 0.028 m/s
Explanation:
In this case you take into account that all the elastic potential of the box, when the spring is compressed is equal to the kinetic energy of the box before it hits the spring. That is:
(1)
m: mass of the box = 4.5kg
k: spring constant = 85N/m
x: compression of the spring = 6.5cm = 0.0065m
You solve the equation (1) for v:
(2)
Next, you replace the values of the parameters:
The velocity of the box when it hits the spring is 0.028m/s
Answer:
B. When the ball is released, the thrower's arm transfers its energy to the ball.
Answer:
The formula is CH+H2 it’s stable beacuse the to ions h and c make it stable element compound is ready and compactable
Explanation:
Answer:
145 m
Explanation:
Given:
Wavelength (λ) = 2.9 m
we know,
c = f × λ
where,
c = speed of light ; 3.0 x 10⁸ m/s
f = frequency
thus,
substituting the values in the equation we get,
f = 1.03 x 10⁸Hz
Now,
The time period (T) =
or
T = = 9.6 x 10⁻⁹ seconds
thus,
the time interval of one pulse = 100T = 9.6 x 10⁻⁷ s
Time between pulses = (100T×10) = 9.6 x 10⁻⁶ s
Now,
For radar to detect the object the pulse must hit the object and come back to the detector.
Hence, the shortest distance will be half the distance travelled by the pulse back and forth.
Distance = speed × time = 3 x 10^8 m/s × 9.6 x 10⁻⁷ s) = 290 m {Back and forth}
Thus, the minimum distance to target = = 145 m
Answer:
9m
Explanation:
Given parameters:
Volume of the water = 5liters;
Since density = 1g/cm³
1L = 1000cm³
5L = 5000cm³
So;
mass = density x volume = 1 x 5000 = 5000g ; 5kg
Work done = 450J
Acceleration due to gravity = 10m/s²
Unknown:
Depth of the well = ?
Solution:
To solve this problem;
Work done = mass x gravity x depth
450 = 5 x 10 x depth
depth = 9m