Question

An 8.7 g bullet is accelerated in a rifle barrel 105 cm long to a speed of 465 m/s. Use the work-energy theorem to find the average force exerted on the bullet while it is being accelerated. Answer in units of N.

Answer 1

Answer:896 N

Explanation:

Given

mass of bullet $m=8.7 gm$

Length of barrel $d=105 cm=1.05 m$

final velocity $v=465 m/s$

initial velocity $u=0 m/s$

Work done by all the forces is equal to change in kinetic Energy

$F\cdot d=\frac{1}{2}\times mv^2-0$

$F_{avg}\times 1.05=\frac{1}{2}\times 8.7\times 10^{-3}\times 465^2$

$F_{avg}=\frac{0.5\times 8.7\times 10^{-3}\times 465^2}{1.05}$

$F_{avg}=895.789 Na\pprox 896 N$