Hope you all doing okay

Name 2 forces acting on an object at rest Only need 1 got gravity

mote1985 [20]

You mean like a box sitting on a table.

One force is the force of gravity, pulling downward on the box.

Now, you know that the forces acting on the box must be balanced, because
if they're not, then the box would be accelerating. But it's just sitting there, so
there must be some other force, just exactly the right strength and direction to
exactly cancel the force of gravity on the box, so that the net force on it is zero.

The other force is the force of the table pushing upward on the box. It's called
the "normal force".

7 0

3 years ago

The heliocentric system gained support when Galileo observed that _____.

lianna [129]

Venus goes through phases similar to those of earths moon.

4 0

3 years ago

Two equal magnitude electric charges are separated by a distance d. The electric potential at the midpoint between these two cha

Ann [662]

Answer:

The charges under study are of the same sign

The calculation of the electric field for each charge separately, there is no relationship between the charges

Explanation:

Let's start by writing the equation for the electric field

E = k q / r²

where q is the charge under analysis and r the distance from this charge to a positive test charge.

When analyzing the statement the student has some problems.

* The charges under study are of the same sign, it does not matter if positive or negative.

* The calculation of the electric field for each charge separately, there is no relationship between the charges for the calculation of the electric field.

* What is added is the interaction of the electric field with the positive test charge, in this case each field has the opposite direction to the other, so the vector sum gives zero

8 0

3 years ago

A pilot is flying from DFW to NYC. The air traffic controller directs him to fly 69° Northeast at 243 m/s. What is the y compone

kolezko [41]

Answer:

$v_{y} = 227$ m/s

Explanation:

Assumptions: 0° is true North, and 90° is east (along the x-axis).

To solve this problem we must use the expression:

$v_{y} = v_{0}sin(\theta)$

Where $v_{y}$ is the velocity in the y-direction (East), $v_{0}$ is the total velocity in the direction which the aircraft is travelling, and $\theta$ is the direction the aircraft is travelling (angle from the y-axis).