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Vinvika [58]
1 year ago
12

Hope you all doing okay

Physics
1 answer:
Vsevolod [243]1 year ago
8 0

Answer:Thank you

Explanation:

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Which equation is true of an atom with no elctrical charge
Paladinen [302]

Answer:

Atoms are composed of electrons (charge -1), protons (charge +1), and neutrons (no charge). So in a neutral atom the correct answer is "D".

3 0
3 years ago
A particle with charge 7.76×10^(−8)C is moving in a region where there is a uniform 0.700 T magnetic field in the +x-direction.
kodGreya [7K]

Answer:

The  z-component of the force is  \= F_z  =  0.00141 \ N    

Explanation:

From the question we are told that

          The charge on the particle is q =  7.76 *0^{-8} \  C    

           The magnitude of the magnetic field is  B =  0.700\r i \ T

            The  velocity of the particle toward the x-direction is  v_x  =  -1.68*10^{4}\r  i  \ m/s

           The  velocity of the particle toward the y-direction is

v_y  =  -2.61*10^{4}\ \r j  \ m/s

           The  velocity of the particle toward the z-direction is

v_y  =  -5.85*10^{4}\ \r k  \ m/s

Generally the force on this particle is mathematically represented as

          \= F  =  q (\= v   X  \= B )

So  we have    

          \= F  =  q ( v_x \r  i + v_y \r  j  +  v_z \r k  )  \ \ X \ (  \= B i)

         \= F  = q (v_y B(-\r  k) + v_z B\r j)      

  substituting values

       \= F  = (7.7 *10^{-8})([ (-2.61*10^{4}) (0.700)](-\r  z) + [(5.58*10^{4}) (0.700)]\r y)    

      \= F=  0.00303\ \r j +0.00141\ \r k                  

So the z-component of the force is  \= F_z  =  0.00141 \ N    

Note :  The  cross-multiplication template of unit vectors is  shown on the first uploaded image  ( From Wikibooks ).

7 0
3 years ago
What is the gravitational force on a 70kg that is 6.38x10^6m above the earths surface
NARA [144]

Answer:

171.5 N

Explanation:

The gravitational force on an object due to the Earth is given by

F=mg

where

m is the mass of the object

g is the acceleration due to gravity

The acceleration due to gravity at a certain height h above the Earth is given by

g=\frac{GM}{(R+h)^2}

where:

G is the gravitational constant

M=5.98\cdot 10^{24} kg is the Earth's mass

R=6.37\cdot 10^6 m is the Earth's radius

Here,

h=6.38\cdot 10^6  m

So the acceleration due to gravity is

g=\frac{(6.67\cdot 10^{-11})(5.98\cdot 10^{24})}{(6.37\cdot 10^6 + 6.38\cdot 10^6)^2}=2.45 m/s^2

We know that the mass of the object is

m = 70 kg

So, the gravitational force on it is

F=mg=(70)(2.45)=171.5 N

5 0
3 years ago
2. For a rotating rigid body, which of the following statements is NOT correct?
AfilCa [17]

Answer:

                                                dasgfwe

Explanation:

6 0
3 years ago
Un comerciante compra 300 litros de aceite a 3 L y los vendió 5 L qué beneficio obtuvo​
andre [41]
El beneficio que obtuvo es de 2 L
5 0
3 years ago
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