Question

A position vector in the first quadrant has an x-component of 6 m and a magnitude of 10 m. What is the value of its y-component

Answer 1

Answer:

8m

Explanation:

The magnitude m of a vector (x, y) is given by

m = $\sqrt{x^2 + y^2}$      -------------------------(i)

where;

x and y are the x- and y- components of the vector.

From the question;

m = 10m

x = 6m

Substitute these values into equation (i) as follows;

10 = $\sqrt{6^2 + y^2}$

Solve for y;

Find the square of both sides

10² = 6² + y²

100 = 36 + y²

y² = 100 - 36

y² = 64

y = √64

y = 8

Therefore, the y-component of the position vector is 8m