A position vector in the first quadrant has an x-component of 6 m and a magnitude of 10 m. What is the value of its y-component
1 answer:
Answer:
8m
Explanation:
The magnitude m of a vector (x, y) is given by
m = -------------------------(i)
where;
x and y are the x- and y- components of the vector.
From the question;
m = 10m
x = 6m
Substitute these values into equation (i) as follows;
10 =
Solve for y;
<em>Find the square of both sides</em>
10² = 6² + y²
100 = 36 + y²
y² = 100 - 36
y² = 64
y = √64
y = 8
Therefore, the y-component of the position vector is 8m
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Refer to the diagram shown.
There are twelve 5-minute divisions.
Each 5-minute division is equal to 360°/12 = 30°.
By convention, angles are measured counterclockwise from the positive x-axis.
The angular position of the minute hand at 2:55 is
θ = 90° + 30° = 120°
Because 360° = 2π radians, therefore
θ = (120/360)*2π = (2π)/3 radians = 2.0944 radians
Answer: (2π)/3 radians ofr 2.0944 radians.
There are twelve 5-minute divisions.
Each 5-minute division is equal to 360°/12 = 30°.
By convention, angles are measured counterclockwise from the positive x-axis.
The angular position of the minute hand at 2:55 is
θ = 90° + 30° = 120°
Because 360° = 2π radians, therefore
θ = (120/360)*2π = (2π)/3 radians = 2.0944 radians
Answer: (2π)/3 radians ofr 2.0944 radians.
The weight of an object mass of 100 kg on the surface of a Planet willl is 981 N.
<h3>What is weight?</h3>
The weight of matter is found as the product of the mass and the gravitational acceleration;
Given data;
Weight of an object,W =?
Mass,m = 100 kg
Hence the weight of an object willl be 981 N.
To learn more about the weight refer;
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