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soldi70 [24.7K]
3 years ago
13

A position vector in the first quadrant has an x-component of 6 m and a magnitude of 10 m. What is the value of its y-component

Physics
1 answer:
LUCKY_DIMON [66]3 years ago
7 0

Answer:

8m

Explanation:

The magnitude m of a vector (x, y) is given by

m = \sqrt{x^2 + y^2}      -------------------------(i)

where;

x and y are the x- and y- components of the vector.

From the question;

m = 10m

x = 6m

Substitute these values into equation (i) as follows;

10 = \sqrt{6^2 + y^2}

Solve for y;

<em>Find the square of both sides</em>

10² = 6² + y²

100 = 36 + y²

y² = 100 - 36

y² = 64

y = √64

y = 8

Therefore, the y-component of the position vector is 8m

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"Every action has equal but opposite reaction"

By the data given in question, Albert was pressing the book against the wall.Now, Albert started to reduce his force up against the wall.

First we have to consider all the forces applied on book in this scenario.

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Neither mass nor acceleration due to gravity changed, so weight acting upon the book will remain same.

2. When Albert reduced force, normal reaction of wall reduced against it according to Newton's third law of motion

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Notice that maximum static friction will hinder the book from movement, since Albert reduced his force, but wight didn't pull the book, which means that maximum static friction increased to hinder downward motion.

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