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4 years ago

Of the three forces acting on the rock as it slides down the bowl, which (if any) are constant and which are not? explain.

Physics

1 answer:

choli [55]4 years ago

6 0

Answer

Hi,

The forces are; weight (gravity), Normal/centripetal force and friction. Force due to gravity is constant where as friction and centripetal are not.

Explanation

Weight is constant, given by the force of gravity on the object. The centripetal force is a function of the angles occurring between the velocity vector and the weight vector that is at right angle with the perpendicular line drawn from the surface. Friction is a function of the centripetal force thus it also varies.

Hope this helps!

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3 years ago

A balloon has a volume of 8.5 L at a pressure of 150 kPa. What will be the new volume when the pressure drops to 55.0 kPa?

lukranit [14]

Answer:

V₂ = 23.18 L

Explanation:

Given that,

Initial volume of a balloon, V₁ = 8.5 L

Initial pressure, P₁ = 150 kPa

We need to find new volume when the pressure drops to 55 kPa.

It is based on the concept of Boyle's law. The mathematical form of the Boyle's law is given by :

$P_1V_1=P_2V_2\\\\V_2=\dfrac{P_1V_1}{P_2}\\\\V_2=\dfrac{150\times 8.5}{55}\\\\=23.18\ L$

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3 years ago

What is the material conditional. The subject is philosophy

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4 years ago

1. Determine whether or not the equation below is balanced. If it isn't balanced, write the balanced

Ann [662]

Answer:

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7 0

3 years ago

Read 2 more answers

It is common to see birds of prey rising upward on thermals. The paths they take may be spiral-like. You can model the spiral mo

TiliK225 [7]

Answer:

a) $8.115 m/s$

b) $9.472 m/s^{2}$

c) $21.7\°$

Explanation:

The rest of the question is written below:

Determine (a) the bird’s speed relative to the ground; (b) the bird’s acceleration (magnitude and direction); and (c) the angle between the bird’s velocity vector and the horizontal.

<u>And we have the following data:</u>

$r=6 m$ is the radius of the circular path in the x-axis

$T=5 s$ the period of the circular motion of the bird's path

$V_{y}=3 m/s$ the vertical component of the bird's velocity, which is directed upward and is constant.

Now let's begin with the answers:

<h3>a) Bird’s speed relative to the ground</h3>

In order to find this speed, we have to calculate the magnitude of the bird's velocity vector:

$V=sqrt{{V_{x}}^{2} + {V_{y}}^{2}$ (1)

We already know the value of $V_{y}$ . So, we have to find $V_{x}$ .

Since the bird is describing a circular path in the x-axis, $V_{x}$ will be its <u>tangential velocity</u>:

$V_{x}=\omega r=\frac{2 \pi}{T} r$ (2)

Where $\omega=\frac{2 \pi}{T}$ is the <u>birds angular velocity</u>

$V_{x}=\frac{2 \pi}{5 s} 6 m$ (3)

$V_{x}=7.539 m/s$ (4)

Substituting (4) in (1):

$V=sqrt{(7.539 m/s)}^{2} + (3 m/s)^{2}$ (5)

$V=8.1147 m/s \approx 8.115 m/s$ (6) This is the bird's speed relative to the ground

<h3>b) Bird’s acceleration (magnitude and direction)</h3>

Since the vertical component of the bird's velocity is constant, the vertical component of its acceleration is zero:

$a_{y}=0 m/s^{2}$

However, the bird has radial acceleration $a_{r}=a_{x}$ that results from its rotation on the circular path horizontally:

$a_{x}=\frac{{V_{x}}^{2}}{r}$ (7)

$a_{x}=\frac{(7.539 m/s)^{2}}{6 m}$ (8)

$a_{x}=9.472 m/s^{2}$ (9) This is the magnitude of the bird's acceleration, which is directed to the center of the circular path the bird describes while it is moving upwards in the spiral.

<h3>c) Angle between the bird’s velocity vector and the horizontal</h3>

In order to find the direction of the bird's velocity vector with the horizontal, we have to find the angle between the horizontal and the vertical component of this velocity:

$\theta=tan^{-1}(\frac{V_{y}}{V_{x}})$ (10)

$\theta=tan^{-1}(\frac{3 m/s}{7.539 m/s})$ (11)

Finally:

$\theta=21.69\° \approx 21.7 \°$ (12)

6 0

4 years ago