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brilliants [131]

3 years ago

7

Waves from two slits are in phase at the slits and travel to a distant screen to produce the second minimum of the interference

pattern. The difference in the distance traveled by the wave is:

1 answer:

bazaltina [42]3 years ago

5 0

Answer:

Three halves of a wavelength I.e 7lambda/2

Explanation:

See attached file pls

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A sound wave travels at 379 m/sec and has a wavelength of 8 meters. Calculate its frequency and period.

olga nikolaevna [1]

$\qquad\qquad\huge\underline{{\sf Answer}}$

Wavelength, Wavespeed and frequency depends on each other in the following way :

$\qquad \sf \dashrightarrow \: frequency = \dfrac{wave \: \: velocity}{wavelength}$

$\qquad \sf \dashrightarrow \: f = \dfrac{389}{8}$

$\qquad \sf \dashrightarrow \: f \approx 48.62 \: \: hertz$

And we know the Reciprocal relationship between frequency and period ~

So, let's find it's period •

$\sf{\qquad \sf \dashrightarrow \: t = \dfrac{8}{389}}$

$\sf{\qquad \sf \dashrightarrow \: t \approx 0.02 sec }$

6 0

2 years ago

At one particular moment, a 19.0 kg toboggan is moving over a horizontal surface of snow at 4.00 m/s. After 7.00 s have elapsed,

Lina20 [59]

Answer:

10.86 N

Explanation:

Let the average frictional force acting on the toboggan be 'f' N.

Given:

Mass of toboggan (m) = 19.0 kg

Initial velocity (u) = 4.00 m/s

Final velocity (v) = 0 m/s

Time for which friction acts (Δt) = 7.00 s

Now, change in momentum is given as:

$\Delta p =Final\ momentum-Initial\ momentum\\\\\Delta p=mv-mu\\\\\Delta p=19.0\ kg(0-4.00)\ m/s\\\\\Delta p=-76.00\ Ns$

Now, we know that, change in momentum is equal to the impulse acting on the body. So,

Impulse is, $J=\Delta p=-76.00\ Ns$

Now, we know that, impulse is also given as the product of average force and the time interval for which it acts. So,

$J=f\times \Delta t$

Rewriting the above equation in terms of 'f', we get:

$f=\dfrac{J}{\Delta t}$

Plug in the given values and solve for 'f'. This gives,

$f=\frac{-76.00\ Ns}{7.00\ s}\\\\f=-10.86\ N$

Therefore, the magnitude of frictional force is $|f|=|-10.86\ N|=10.86\ N$

3 0

3 years ago

Please help on this one somebody? :)

ahrayia [7]

ans D. Substance B has a greater latent heat of vaporization than substance A.

8 0

3 years ago

Two of the types of infrared light, ir-c and ir-a, are both components of sunlight. their wavelengths range from 3000 to 1,000,0

NikAS [45]

The energy of a light wave is calculated using the formula
E = hc/λ
h is the Planck's constant
c is the speed of light
λ is the wavelength
For the ir-c, the range is
<span>6.63 x 10^-34 (3x10^8) / 3000 = 6.63 x 10 ^-29 J
</span>6.63 x 10^-34 (3x10^8) / 1000000 = 1.99 x 10^-31 J

For the ir-a, the range is
6.63 x 10^-34 (3x10^8) / 700 = 2.84 x 10^-28 J
6.63 x 10^-34 (3x10^8) / 1400 = 1.42 x 10^-28 J

6 0

3 years ago

Read 2 more answers

The acceleration of a block attached to a spring is given by a=−(0.324m/s2)cos([2.50rad/s]t) a = − ( 0.324 m / s 2 ) c o s ( [ 2

allsm [11]

Answer:

Looks like you have:

a = -.324 cos 2.5 t

In this case ω^2 A = .324

ω = 2.5

f = ω / (2 * pi) = 2.5 / 6.28 = .40 / sec

5 0

2 years ago