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tekilochka [14]
3 years ago
14

In a white dwarf, electrons are packed in so tightly that they physically cannot get any closer to one another. This provides an

overall outward force, similar to the white dwarf’s thermal pressure but much stronger, called electron degeneracy pressure, which does not depend on the temperature of the material. A white dwarf no longer has any ongoing energy production from nuclear fusion, so it will continuously cool off with time. Taking into consideration all the forces acting on each piece of the white dwarf, what will happen to it as it cools?
Physics
1 answer:
Natalka [10]3 years ago
4 0

Answer:

The white dwarf will start to get darker.

Explanation:

The white dwarf will keep is spherical shape, since electron degeneracy pressure (outward direction) will counteract the force of gravity due to its own mass (inward direction) which lead to hydrostatic equilibrium.

A nuclear reaction occurs when light elements combine into heavier elements (that is know as nucleosynthesis). Exist different ways in which that can happen, but the most common is the Proton-Proton chain. In that fusion reaction, two atoms of Hydrogen combine to form helium, while the fusion takes place, photons are created.

Photons are the elementary particles that constitute light and taking into account that in white dwarfs the production of photons has ceased because there are no nuclear fusions, then, it is clear that the white dwarf will start to get darker as it cools since is emitting into space the photons produced in the past.

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Explanation:

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If a person consumes an extra 500 calories per day, how long would it take before he or she gained one pound of fat?
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The answer is A. 10 days
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4 years ago
5. A family of ducks is swimming in a pond at a speed of 3 m/s when a gust of wind hits them. By the time they reach the other s
ella [17]

Answer:

The time taken by the duck to cross the lake is, t= 4 s

Explanation:

Given data,

The initial speed of the ducks, u = 3 m/s

The final speed of the ducks, v = 7 m/s

The acceleration of the duck, a = 1 m/s²

The formula for the acceleration is,

                               a = (v - u) / t

∴                               t = (v - u) / a

Substituting the given values in the above equation,

                                t = (7 - 3) / 1

                                  = 4 s

Hence, the time taken by the duck to cross the lake is, t= 4 s

6 0
4 years ago
A car with a momentum (impulse) of 20,000 kg m/s collides with a wall and comes to a rest in 0.1 seconds. How much
Pani-rosa [81]

Answer:

» Force is 200,000 Newtons

Explanation:

{ \tt{force =  \frac{impulse}{time} }} \\  \\ { \tt{force =  \frac{20000}{0.1} }} \\  \\ { \tt{force = 200000 \: newtons}}

8 0
3 years ago
Read 2 more answers
Suppose that Hubble's constant were H0 = 51 km/s/Mly (which is not its actual value). What would the approximate age of the univ
bija089 [108]

Given the Hubble's constant, the approximate age of the universe is 5.88 × 10⁹ Years.

Given the data in the question;

Hubble's constant; H_0 = 51km/s/Mly

Age of the universe; t = \ ?

We know that, the reciprocal of the Hubble's constant ( H_0 ) gives an estimate of the age of the universe ( t ). It is expressed as:

Age\ of\ Universe; t = \frac{1}{H_0}

Now,

Hubble's constant; H_0 = 51km/s/Mly

We know that;

1\ light\ years = 9.46*10^{15}m

so

1\ Million\ light\ years = [9.46 * 10^{15}m] * 10^6 = 9.46 * 10^{21}m

Therefore;

H_0 = 51\frac{km}{\frac{s}{Mly} } = 51000\frac{m}{s\ *\ Mly}  \\\\H_0 = 51000\frac{m}{s\ *\ (9.46*10^{21}m)} \\\\H_0 =  5.39 *10^{-18}s^{-1}\\

Now, we input this Hubble's constant value into our equation;

Age\ of\ Universe; t = \frac{1}{H_0}\\\\t = \frac{1}{ 5.39 *10^{-18}s^{-1}} \\\\t = 1.855 * 10^{17}s\\\\We\ convert\ to\ years\\\\t =  \frac{ 1.855 * 10^{17}}{60*60*24*365}yrs \\\\t = \frac{ 1.855 * 10^{17}}{31536000}yrs\\\\t = 5.88 *10^9 years

Therefore, given the Hubble's constant, the approximate age of the universe is 5.88 × 10⁹ Years.

Learn more: brainly.com/question/14019680

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