1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Shkiper50 [21]
3 years ago
8

If you start with 500.0 g of a radioisotope with a half-life of 3.0 days, how much of the original isotope will still be in the

sample after 18 days?
Chemistry
2 answers:
fomenos3 years ago
8 0
Half life means it decrease by half every 3 days
250 - 3 days
125 - 6 days
62.5 - 9 days
31.25 - 12 days
15.625 - 15 days
7.8125 - 18 days
7.8125 is your final answer.

Your welcome.
Please mark me the brainliest if your are satisfied. 
ValentinkaMS [17]3 years ago
6 0
After 3 days  = 500g becomes 250g
After 6 days  = 250g becomes 125g
After 9 days  = 125g becomes 62.5g
After 12 days = 62.5g becomes 31.25g
After 15 days = 31.25g becomes 15.625g
After 18 days = 15.625g becomes 7.8125g

After 18days, you would have about 7.813g left.
You might be interested in
Liquid A and liquid B form a solution that behaves ideally according to Raoult's law. The vapor pressures of the pure substances
Rama09 [41]

Answer:

Vapor pressure of solution → 151.1 Torr

Option 2.

Explanation:

Raoult's Law is relationed to colligative property about vapor pressure. A determined solute, can make, the vapor pressure of solution decreases.

ΔP = P° . Xm

where Xm is the mole fraction of solute, P° (vapor pressure of pure solvent)

and ΔP = Vapor pressure of pure solvent - Vapor pressure of solution.

In order to determine the vapor pressure of solution, we need to determine, the vapor pressure of B and A in the solution

B's pressure = P° B . Xm

When we add A to B, A works as the solute and B, as the solvent.

Vapor pressure of pure B is 135 torr. (P° B)

In order to determine, the Xm, we use the moles of A and B

Xm = 5.3 mol of B / (1.28 + 5.3) → 0.806

B's pressure = 135 Torr . 0.806 → 108.81 Torr

If mole fraction of B is 0.806, mole fraction for A (solute) will be (1 - 0.806)

A's pressure = 218 Torr . 0.194 → 42.3 Torr

Vapor pressure of solution is sum of vapor pressures of solute + solvent.

Vapor pressure of solution = 42.3 Torr + 108.81 Torr → 151.1 Torr

6 0
3 years ago
In caves, dripping groundwater containing calcium bicarbonate can form stalactites and stalagmites. When the water is exposed to
Pepsi [2]
This is a chemical change because there is a new substance that was created and the new chemical can cause other chemical reaction to happen compared to the 1st state of chemical that was in the cave. Because the cave water was exposed to another environment, the calcium bicarbonate, which is also known as salt. When the cave's groundwater was exposed to a different environment the atom in the cave water rearranged and crystallized.  
7 0
3 years ago
Read 2 more answers
What event happens underwater to cause a tsunami?
azamat
The Earth's crust or is it the continental plates one of the two but they push against each other costing a tsunami.
8 0
3 years ago
What is the mass of oxygen in 3.34 g of potassium permanganate?
3241004551 [841]

Answer:

1.35 g

Explanation:

Data Given:

mass of Potassium Permagnate (KMnO₄) = 3.34 g

Mass of Oxygen: ?

Solution:

First find the percentage composition of Oxygen in Potassium Permagnate (KMnO₄)

So,

Molar Mass of KMnO₄ = 39 + 55 + 4(16)

Molar Mass of KMnO₄ = 158 g/mol

Calculate the mole percent composition of  Oxygen in Potassium Permagnate (KMnO₄).

Mass contributed by Oxygen (O) = 4 (16) = 64 g

Since the percentage of compound is 100

So,

                        Percent of Oxygen (O) = 64 / 158 x 100

                        Percent of Oxygen (O) = 40.5 %

It means that for ever gram of Potassium Permagnate (KMnO₄) there is 0.405 g of Oxygen (O) is present.

So,

for the 3.34 grams of Potassium Permagnate (KMnO₄) the mass of Oxygen will be

                  mass of Oxygen (O) = 0.405 x 3.34 g

                  mass of Oxygen (O) = 1.35 g

5 0
3 years ago
How many moles of hydrogen atoms are in 1 mole of sulfuric acid?
Hunter-Best [27]

one mole of sulfuric acid will contain 2 moles of hydrogen atoms. The molar mass of sulfuric acid is 98.0795 g/mol. This means that every mole of sulfuric acid has a mass of 98.0795 g. Since you're dealing with one mole of sulfuric acid, it follows that you will also be dealing with two moles of hydrogen.

4 0
3 years ago
Other questions:
  • How many significant figures does 104,000 have
    12·1 answer
  • The element nitrogen has an atomic weight of 14.0 and consists of two stable isotopes nitrogen-14 and nitrogen-15. The isotope n
    12·1 answer
  • Explain the difference between fixed and variable oxidation
    7·1 answer
  • Deciding that she was thirsty, Ms. Smith decided to mix up some lemonade using 2 tablespoons of lemonade, and 2 cups of water. W
    14·1 answer
  • The following is a chemical reaction for _______ with ozone.
    10·2 answers
  • Professionals in a scientific laboratory and in the healthcare field need to accurately prepare solutions for a number of reason
    10·1 answer
  • A clay ball (50 degrees Fahrenheit) is placed in a bucket of water (80 degrees Fahrenheit.) which scenario describes how heat en
    11·2 answers
  • When aluminium and chlorine compared , which has smaller atomic size ? Why ?​
    13·2 answers
  • B. If the initial pressure of gas inside the balloon was 1.65 atm, what is the new pressure?
    6·1 answer
  • Perform the following calculation and report the answer with the correct number of significant figures.
    12·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!