This should help
1 kPa = 1000 pascals (Pa)
1 mmHg = 133.322 pascals (Pa)
kPa value x 1000 Pa = mmHg value x 133.322 Pa.
kPa value = mmHg value x 0.133322
Neon gas consist of individual, unbonded neon atoms due to the stable (octet) configuration, while chlorine exists as diatomic chlorine molecules to gain stability.
<h3>How we define the stability of atoms?</h3>
Stability of any atom will be defined on the basis of the electronic configuration or the number of valence shell electrons they have.
- Chlorine atom have seven electrons on the outermost shell of the atom and will able to gain 1 electron to get octet configuration, that's why present in the diatomic form.
- Neon is a noble gas as they have stable configuration due to presence of 8 electrons in the valence shell, and due to stability it will not easily react with any other gas and present in single atomic form.
Hence due to stable configuration of neon it is present in the unbonded form.
To know more about octet configuration, visit the below link:
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Answer:
investing money in the ratio 3:2. After 6 months, they made a profit of 350,000. Anil wanted to share the money equally. Ashok felt he should get 30,000 and Anil should get 320,000.
Answer:
1. ![K_eq = [Ca^{2+][OH^-]^2 = K_{sp}](https://tex.z-dn.net/?f=K_eq%20%3D%20%5BCa%5E%7B2%2B%5D%5BOH%5E-%5D%5E2%20%3D%20K_%7Bsp%7D)
2. a. No effect;
b. Products;
c. Products;
d. Reactants
Explanation:
1. Equilibrium constant might be written using standard guidelines:
- only aqueous species and gases are included in the equilibrium constant excluding solids and liquids;
- the constant involves two parts: in the numerator of a fraction we include the product of the concentrations of products;
- the denominator includes the product of the concentrations of reactants;
- the concentrations are raised to the power of the coefficients in the balanced chemical equation.
Based on the guidelines, we have two ions on the product side, a solid on the left side. Thus, the equilibrium constant has the following expression:
![K_eq = [Ca^{2+][OH^-]^2 = K_{sp}](https://tex.z-dn.net/?f=K_eq%20%3D%20%5BCa%5E%7B2%2B%5D%5BOH%5E-%5D%5E2%20%3D%20K_%7Bsp%7D)
2. a. In the following problems, we'll be considering the common ion effect. According to the principle of Le Chatelier, an increase in concentration of any of the ions would shift the equilibrium towards the formation of our precipitate.
In this problem, we're adding calcium carbonate. It is insoluble, so it wouldn't have any effect on the equilibrium.
b. Sodium carbonate is completely soluble, it would release carbonate ions. The carbonate ions would combine with calcium cations and more precipitate would dissolve. This would shift the equilibrium towards formation of the products to reproduce the amount of calcium cations.
c. HCl would neutralize calcium hydroxide to produce calcium chloride and water, so the amount of calcium ions would increase, therefore, the products are favored.
d. NaOH contains hydroxide anions, so we'd have a common ion. An increase in hydroxide would produce more precipitate, so our reactants are favored.