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hoa [83]
3 years ago
8

A system dissipates 12 J of heat into the surroundings; meanwhile, 28 J of work is done on the system. What is the change of the

internal energy ΔEth of the system? A system dissipates 12 of heat into the surroundings; meanwhile, 28 of work is done on the system. What is the change of the internal energy of the system? a. -40 J b. -16 J c. 16 J d. 40 J
Physics
1 answer:
timurjin [86]3 years ago
6 0

Answer:

option C

Explanation:

given,

energy dissipated by the system to the surrounding = 12 J

Work done on the system = 28 J

change in internal energy of the system

Δ U = Q - W

system losses energy = - 12 J

work done = -28 J

Δ U = Q - W

Δ U = -12 -(-28)

Δ U = 16 J

hence, the correct answer is option C

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motikmotik

Answer:

Explanation:

1) Displacement of the object will be gotten using simply adding the distances since they are goinf in the same direction (positive y direction)

Displacement= 330km + 220km

Displacement = 550km North

2) For a falling body, the body will possess positive acceleration due to gravity because it is falling under the influence of gravitational force. If a body is not under the influence of gravity and is thrown up, such body wont come back down. Hence the value of acceleration due to gravity of a body falling to the ground is +9.8 m/s² (note that the unit of acceleration is m/s²)

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You are traveling along a freeway at 65 mi/h. You suddenly skid to a stop because of congestion in traffic. Where is the energy
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The work and energy theorem allows finding the result for where the kinetic energy of the car is before stopping is:

    The energy becomes:

  • An important part in work on discs.
  • A part in non-conservative work due to friction.

Work is defined by the scalar product of force and displacement.

          W = F . d

Where the bold indicate vectors, W is work, F is force and d is displacement.

The work energy theorem relates work and kinetic energy.

            W = ΔK = K_f - K_o

In this case the vehicle stops therefore its final kinetic energy is zero, consequently the work is:  

          W = - K₀

Therefore, the initial kinetic energy that the car has is converted into work in its brakes.  In reality, if assuming that there is friction, an important part is transformed into non-conservative work of the friction force, this work can be seen in a significant increase in the temperature of the discs on which the work is carried out.

In conclusion, using the work-energy theorem we can find the result for where the kinetic energy of the car is before stopping is:

    The energy becomes:

  • An important part in work on the discs.
  • A part in non-conservative work due to friction.

Learn more here:  brainly.com/question/17056946

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For the sake of easiness and the fact negatives are annoying, I will assume east to be positive.

So we know 9.4m - 15840 = (1320+m)*1.5
9.4m - 15840 = 1980+1.5m

Rearranging to solve for m
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