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notsponge [240]
4 years ago
14

Consider this reaction. What volume (in milliliters) of oxygen gas is required to react with 4.03 g of Mg at STP? 1860 mL 2880 m

L 3710 mL 45,100 mL
Chemistry
2 answers:
charle [14.2K]4 years ago
4 0
<span>Step 1: find number of moles of Mg(divide 4.03 by its molor mass)
step 2:find number of moles in O2
step 3: remember STP is 22.4 L = 1 mole</span>
step 4: multiply 0.0829mol O₂ by 22.4L/mol to get 1.857L
answer is 1860 mL
Sholpan [36]4 years ago
4 0

Answer: 1860 mL

Explanation:

2Mg+O_2\rightarrow 2MgO

According to Avogadro's law , 1 mole of every gas occupies 22.4 L at standard temperature and pressure and 1 mole of every substance weighs equal to its molar mass.

2moles=2\times 24.305=48.61g of Magnesium reacts with 22.4 L of oxygen gas STP.

4.03g of  Magnesium reacts with=\frac{22.4L}{48.61g}\times 4.03g=1.86L=1860ml of oxygen gas STP.

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A chemist needs to make 250 mL of a 2.50 M aqueous solution of ammonium hydroxide from a 6.00 M ammonium hydroxide solution. How
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Answer:

250 mL (total solution)  = 104 mL (stock solution)  + 146 mL (water)

Explanation:

Data Given

M1 = 6.00 M

M2 = 2.5 M

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V2 = ?

Solution:

As the chemist needs to prepare 250 mL of solution from 6.00 M ammonium hydroxide solution to prepare a 2.50 M aqueous solution of ammonium hydroxide.

Now

first he have to determine the amount of ammonium hydroxide solution that will be taken from6.00 M ammonium hydroxide solution

For this Purpose we use the following formula

                    M1V1=M2V2

Put values from given data in the formula

                   6 x V1 = 2.5 x 250

Rearrange the equation

                   V1 = 2.5 x 250 /6

                    V1 = 104 mL

So 104 mL is the volume of the solution which we have to take from the 6.00 M ammonium hydroxide solution to prepare 2.5 M  aqueous solution of ammonium hydroxide

But we have to prepare 250 mL of the solution.

so the chemist will take 104 mL from 6.00 M ammonium hydroxide solution and have to add 146 mL water to make 250 mL of new solution.

in this question you have to tell about the amount of water that is 146 mL

250 mL (total solution)  = 104 mL (stock solution)  + 146 mL (water)

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