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3 years ago

Which of the following is not a symbol used in chemical equations?

Chemistry

1 answer:

kkurt [141]3 years ago

5 0

Explanation:

The following representations are the symbols that are being used in chemical equations.

- All representations of elements in the periodic table

- (s) solid state

- (g) gaseous state

- (l) liquid state

- (aq) aqueus solution

- ∆ indicates the application of heat

- →← Forward and Backward direction

- ⇄ Reversible reaction

Anything outside these symbols are not being used in chemical equations.

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How do I describe an ion?

worty [1.4K]

Answer:

Explanation:

How do I describe an ion?

<h2>an ion is an atom that has had electrons added or taken away from it.</h2><h2>they do this in order to obtain a stable electronic configuration like their closest noble gas..see Periodic Table column 18 which is also column VIIIA</h2><h2>If they gain electrons, they are negative and are called</h2><h2>ANIONS</h2><h2>if they lose electrons they are positive and are called</h2><h2>CATIONS </h2><h2 />

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3 years ago

How many moles are in 109 grams of kf

lions [1.4K]

Answer:

Explanation:

Molar mass of KF= 39 + 19= 58g/mol

Mass of KF = 109g

Amount = mass/molar mass

Amount = 109/58

Amount = 1.9moles

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3 years ago

The world's record in the 100 m dash is 9.69 seconds and in the 100 yard dash is 9.21 seconds.

Andrews [41]

Speed is equivalent to the distance traveled divided by the time it takes to travel that certain distance.
To solve this problem convert the units first from meter and yards to miles. 100 metes is 0.0621371mi and 100 yards is 0.0568182 yard. 9.69s = 0.002691667 hr and 9.21s = 0.002558333

A.) 23mi/hr
B.) 22.20mi/hr

8 0

3 years ago

Read 2 more answers

One mole of an ideal gas is expanded from a volume of 1.00 liter to a volume of 8.00 liters against a constant external pressure

Leya [2.2K]

Answer : The work done on the surroundings is, 709.1 Joules.

Explanation :

The formula used for isothermally irreversible expansion is :

$w=-p_{ext}dV\\\\w=-p_{ext}(V_2-V_1)$

where,

w = work done

$p_{ext}$ = external pressure = 1.00 atm

$V_1$ = initial volume of gas = 1.00 L

$V_2$ = final volume of gas = 8.00 L

Now put all the given values in the above formula, we get :

$w=-p_{ext}(V_2-V_1)$

$w=-(1.00atm)\times (8.00-1.00)L$

$w=-7L.atm=-7\times 101.3J=-709.1J$

The work done by the system on the surroundings are, 709.1 Joules. In this, the negative sign indicates the work is done by the system on the surroundings.

Therefore, the work done on the surroundings is, 709.1 Joules.

4 0

3 years ago

It takes 839./kJmol to break a carbon-carbon triple bond. Calculate the maximum wavelength of light for which a carbon-carbon tr

tresset_1 [31]

Answer:

The maximum wavelength of light for which a carbon-carbon triple bond could be broken by absorbing a single photon is 143 nm.

Explanation:

It takes 839 kJ/mol to break a carbon-carbon triple bond.

Energy required to break 1 mole of carbon-carbon triple bond = E = 839 kJ

E = 839 kJ/mol = 839,000 J/mol

Energy required to break 1 carbon-carbon triple bond = E'

$E'=\frac{ 839,000 J/mol}{N_A}=\frac{839,000 J}{6.022\times 10^{23} mol^{-1}}=1.393\times 10^{-18} J$

The energy require to single carbon-carbon triple bond will corresponds to wavelength which is required to break the bond.

$E'=\frac{hc}{\lambda }$ (Using planks equation)

$\lambda =\frac{6.626\times 10^{-34} Js\times 3\times 10^8 m/s}{1.393\times 10^{-18} J}$

$\lambda =1.427\times 10^{-7} m =142.7 nm = 143 nm$

$(1 m = 10^9 nm)$

The maximum wavelength of light for which a carbon-carbon triple bond could be broken by absorbing a single photon is 143 nm.

6 0

3 years ago