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Step2247 [10]
3 years ago
9

How is a lithium atom (Li) different from a lithium ion (Li+)?

Chemistry
2 answers:
timofeeve [1]3 years ago
8 0

Answer:

Li has fewer protons than Li+

zalisa [80]3 years ago
8 0
Li has fewer electrons than Li+
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the waves have a trough

Explanation:

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How is radiant energy transformed into chemical energy?
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Photosynthesis is the transformation of radiant energy to chemical energy. Plants take in water, carbon dioxide, and sunlight and turn them into glucose and oxygen. Called photosynthesis, one of the results of this process is that carbon dioxide is removed from the air.

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Assume that 1.0 mol of C4H10 is completely burned in excess oxygen to form carbon dioxide and water. How many moles of CO2 would
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 C₄H₁₀ + O₂ → CO₂ + H₂O
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1.0 moles               X moles
1.0 mol C₄H₁₀ (\frac{8 mol CO₂}{2 mol C₄H₁₀}) = 4 moles of CO₂
7 0
3 years ago
The illustration to the left represents a mixture of hydrogen ( light blue ) and iodine ( purple ) reacting to form a product. I
Ksju [112]

Answer:

1. Hydrogen Iodide

2. 6 molecules of Hydrogen Iodide

3. Iodine is the limiting reagent

Explanation:

The image of the illustration in the question has been attached:

1. The illustration represents a mixture of hydrogen ( light blue ) and iodine ( purple )

H₂ + I₂ ---> 2HI

This forms hydrogen iodide.

2. In the given illustration, 6 product molecules of Hydrogen Iodide. This is indicated in the box on the right side of the illustration.

3.  The limiting reagent is the reactant that determines how much of the products are made. It is the substance that is totally consumed when the chemical reaction is completed. In the box on the right side of the illustration, you will see that hydrogen which is indicated by blue is in excess. The limiting reagent is the one that is completely consumed which is the iodine.

8 0
3 years ago
Immunoglobulin G (IgG), formerly called gamma globulin, is a principal antibody in blood serum. A 0.470 g sample of immunoglobul
Nookie1986 [14]

The molecular mass of the immunoglobulin G, given the data from the question is 1.53×10⁵ g/mole

<h3>How to determine the molarity</h3>

We'll begin by calculating the molarity of the immunoglobulin G. This is illustrated below:

  • Volume = 0.106 L
  • Temperature (T) = 25 °C = 25 + 273 = 298 K
  • Osmotic pressure (π) = 0.733 mbar = 0.733 × 0.000987 = 0.00072 atm
  • Gas constant (R) = 0.0821 atm.L/Kmol
  • Van't Hoff factor (i) = 1
  • Molarity (M)

π = iMRT

M = π / iRT

M = 0.00072 / (1 × 0.0821 × 298)

M = 0.000029 M

<h3>How to determine the mole of immunoglobulin G</h3>
  • Molarity = 0.000029 M
  • Volume = 0.106 L
  • Mole =?

Mole = Molarity × volume

Mole = 0.000029 × 0.106

Mole = 3.074×10⁻⁶ mole

<h3>How to determine the molar mass of mmunoglobulin G</h3>
  • Mole = 3.074×10⁻⁶ mole
  • Mass = 0.470 g
  • Molar mass =?

Molar mass = mass / mole

Molar mass = 0.47 / 3.074×10⁻⁶

Molar mass = 1.53×10⁵ g/mole

Learn more about Osmotic pressure:

brainly.com/question/5925156

#SPJ1

5 0
2 years ago
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