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nikitadnepr [17]
3 years ago
7

Anew fictitious element was discovered. It is a metal named jolmium, J,and it has three valence electrons. If it combineswith io

dine it forms jolmium iodide. Answer the following questions.a.Is this compound ionic or covalent
a. Is this compound ionic or covalent?
b. What is the formula of Jolmium iodide?
c. What is the charge on the metal J in this compound?
d. Explain how you know that is the charge?
Chemistry
1 answer:
cluponka [151]3 years ago
3 0

Answer:

A new fictitious element was discovered.

It is a metal named jolmium, J, and it has three valence electrons.

If it combines with iodine it forms jolmium iodide. Answer the following questions.

a.Is this compound ionic or covalent

b. What is the formula of Jolmium iodide?

c. What is the charge on the metal J in this compound?

d. Explain how you know that is the charge?

Explanation:

It is given the element jolmium J is a metal with three valence electrons.

Since metals are highly electropositive, they lose electrons easily and form cations (Ions with a positive charge).

J^{3+} ion will be formed.

b) The formula of jolmium iodide is shown below:

J^{+3}  I^{-1}\\The formula becomes:\\JI_{3}

a) The compound is ionic in nature.

Since the compound formed between a metal atom and a nonmetal atom will take place by transfer of electrons.

Hence, it is ionic in nature.

c) The charge on the metal J in this compound is +3.

d) Given J has three valence electrons.

That means it can lose three electrons to form a bond.

So, its valency is three.

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torisob [31]

Answer: The correct option for the chemical equation H_3PO_4(aq.)+3LiOH(aq.)\rightarrow Li_3PO_4(aq.)+3H_2O(l) is 1.

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Explanation:

  • For the chemical equation:

H_3PO_4(aq.)+3LiOH(aq.)\rightarrow Li_3PO_4(aq.)+3H_2O(l)

H_3PO_4 is a weak acid and hence will not dissociate into ions whereas LiOH is a strong base and will easily dissociate into ions.

The product Li_3PO_4 is soluble in water and hence, will dissociate into its respective ions. Hence, the ionic equation for this reaction is:

H_3PO_4(aq.)+3Li^{3+}(aq.)+3OH^-(aq.)\rightarrow 3Li^{3+}(aq.)+PO_4^{3-}(aq.)+3H_2O(l)

Net ionic equation becomes:

H_3PO_4(aq.)+3OH^-(aq.)\rightarrow PO_4^{3-}(aq.)+3H_2O(l)

So, the correct option is 1.

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2HBr(aq.)+Co(OH)_2(aq.)\rightarrow CoBr_2(aq.)+2H_2O(l)

HBr and Co(OH)_2 are strong acid and strong base respectively, hence they will easily dissociate into ions.

The product, CoBr_2 is is soluble in water and hence, will dissociate into its respective ions. Hence, the ionic equation for this reaction is:

2H^+(aq.)+2Br^-(aq.)+Co^{2+}(aq.)+2OH^-(aq.)\rightarrow Co^{2+}(aq.)+2Br^-(aq.)+H_2O(l)

The net ionic equation becomes:

H^+(aq.)+OH^-(aq.)\rightarrow H_2O(l)

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7 0
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