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nikitadnepr [17]
3 years ago
7

Anew fictitious element was discovered. It is a metal named jolmium, J,and it has three valence electrons. If it combineswith io

dine it forms jolmium iodide. Answer the following questions.a.Is this compound ionic or covalent
a. Is this compound ionic or covalent?
b. What is the formula of Jolmium iodide?
c. What is the charge on the metal J in this compound?
d. Explain how you know that is the charge?
Chemistry
1 answer:
cluponka [151]3 years ago
3 0

Answer:

A new fictitious element was discovered.

It is a metal named jolmium, J, and it has three valence electrons.

If it combines with iodine it forms jolmium iodide. Answer the following questions.

a.Is this compound ionic or covalent

b. What is the formula of Jolmium iodide?

c. What is the charge on the metal J in this compound?

d. Explain how you know that is the charge?

Explanation:

It is given the element jolmium J is a metal with three valence electrons.

Since metals are highly electropositive, they lose electrons easily and form cations (Ions with a positive charge).

J^{3+} ion will be formed.

b) The formula of jolmium iodide is shown below:

J^{+3}  I^{-1}\\The formula becomes:\\JI_{3}

a) The compound is ionic in nature.

Since the compound formed between a metal atom and a nonmetal atom will take place by transfer of electrons.

Hence, it is ionic in nature.

c) The charge on the metal J in this compound is +3.

d) Given J has three valence electrons.

That means it can lose three electrons to form a bond.

So, its valency is three.

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The equilibrium constant, k of the reaction in which case, the concentrations of the given reactants and products are as indicated is; Choice A; K = 3.1 x 10⁵

<h3>What is the equilibrium constant , k of the reaction as described in the task content?</h3>

It follows from above that the concentrations of the reactants and products are as follows; [H2] = 0.10 M, [N2] = 0.10 M, and [NH3] = 5.6 M at equilibrium.

Hence, the equilibrium constant of the reaction in discuss is;

K = [5.6]²/[0.10]³[0.10]

k = 5.6² × 10⁴

k = 3.136 × 10⁵

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Summarize: Complete the following statements:
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Answer:

Explanation:

Taking into account the definition of Avogadro's Number, the correct answers are:

1 mole of any element contains 6.023×10²³ atoms

1 mole of any compound contains 6.023×10²³ molecules

You have to know that Avogadro's Number or Avogadro's Constant is called the number of particles that make up a substance (usually atoms or molecules) and that can be found in the amount of one mole of said substance. Its value is 6.023×10²³ particles per mole.

Avogadro's number represents a quantity without an associated physical dimension, so it is considered a pure number that allows describing a physical characteristic without an explicit dimension or unit of expression.

Avogadro's number applies to any substance, because the number of elementary units in a mole of a substance is, by definition, a  constant that does not depend on the material or the type of particle considered.

So, in this case, the correct answers are:

1 mole of any element contains 6.023×10²³ atoms

1 mole of any compound contains 6.023×10²³ molecules

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The volume of a gas at 2.0 atm is 3.0 L. What is the volume of the gas at 1.5 atm at the same temperature?
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<u>Answer:</u> The final volume of the gas comes out to be 4 L.

<u>Explanation:</u>

To calculate the volume with changing pressure, we use the equation given by Boyle's law.

This law states that pressure is inversely proportional to the volume of the gas at constant temperature and number of moles.

Mathematically,

P\propto \frac{1}{V}      (At constant temperature and number of moles)

The equation given by this law is:

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Putting values in above equation, we get:

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