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nikitadnepr [17]

3 years ago

7

Anew fictitious element was discovered. It is a metal named jolmium, J,and it has three valence electrons. If it combineswith io

dine it forms jolmium iodide. Answer the following questions.a.Is this compound ionic or covalent
a. Is this compound ionic or covalent?
b. What is the formula of Jolmium iodide?
c. What is the charge on the metal J in this compound?
d. Explain how you know that is the charge?

1 answer:

cluponka [151]3 years ago

3 0

Answer:

A new fictitious element was discovered.

It is a metal named jolmium, J, and it has three valence electrons.

If it combines with iodine it forms jolmium iodide. Answer the following questions.

a.Is this compound ionic or covalent

b. What is the formula of Jolmium iodide?

c. What is the charge on the metal J in this compound?

d. Explain how you know that is the charge?

Explanation:

It is given the element jolmium J is a metal with three valence electrons.

Since metals are highly electropositive, they lose electrons easily and form cations (Ions with a positive charge).

$J^{3+}$ ion will be formed.

b) The formula of jolmium iodide is shown below:

$J^{+3} I^{-1}\\The formula becomes:\\JI_{3}$

a) The compound is ionic in nature.

Since the compound formed between a metal atom and a nonmetal atom will take place by transfer of electrons.

Hence, it is ionic in nature.

c) The charge on the metal J in this compound is +3.

d) Given J has three valence electrons.

That means it can lose three electrons to form a bond.

So, its valency is three.

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Need help !!!!! Stuck asap

Step2247 [10]

<h2>Hello!</h2>

The answer is:

Hence, the new pressure will be 2.07 atm.

$P_{2}=2.07atm$

<h2>Why?</h2>

Since we know that the gas is inside of a rigid container, meaning that the volume will be kept constant, we can solve the problem using the Gay-Lussac's Law.

The the Gay-Lussac's Law establishes that when an ideal gas is kept at the same volume, the pressure and the temperature will be proportional.

We need to pay special attention when we are working with the Gay-Lussac's Law since its equaitons works with absolute temperatures (Kelvin ), so, if we are working with relative temperatures such as Celsius degrees or Fahrenheit degrees, we need to convert the temperatures to Kelvin.

We can convert from Celsius degrees to Kelvin using the following formula:

$Temperature(K)=Temperature(C\°)+273$

So, we have the Gay-Lussac's equation:

$\frac{P_{1}}{T_{1}}=\frac{P_{2}}{T_{2}}$

Also, we are given the following information:

$T_{1}=30\° \\P_{1}=2atm\\T_{2}=40\°$

Therefore, converting the temperature to Kelvin, we have:

$T_{1}=30C\°=30+273K=303K\\\\T_{1}=40C\°=40+273K=313K\\$

Now, calculating we have:

$\frac{P_{1}}{T_{1}}=\frac{P_{2}}{T_{2}}$

$P_{2}=\frac{P_{1}}{T_{1}}*T_{2}\\\\P_{2}=\frac{2atm}{303K}*313K=2.07atm$

Hence, the new pressure will be 2.07 atm.

$P_{2}=2.07atm$

Have a nice day!

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Explanation:

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Answer:

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Explanation:

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Which of the following is true for the equilibrium constant of a reaction?

CaHeK987 [17]

Answer:

The correct answer is <em>It is a ratio of the concentrations in a reaction.</em>

Explanation:

⇒ It is a ratio of the concentrations in a reaction.

This sentence is true because the equilibrium constant is calculated from the product of the concentration of the reaction products divided into the product of the concentrations of the reactants, each concentration raised by the stoichiometric coefficient. For example, for the following reaction:

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The equilibrium constant is expressed as:

$K = \frac{[C]^{c}[D]^{d} }{[A]^{a} [B]^{b} }$

⇒ It remains the same at different temperatures.

The sentence is false because the equilibrium constant changes with the temperature. In general, an endothermic reaction is favored by the increment of temperature (the equilibrium shifts to the right side) and disfavored with the decrease in temperature (shifts to the left).

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This sentence is false because the equilibrium constant is represented with the letter K.

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