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Dahasolnce [82]
1 year ago
12

A gas bottle contains 8. 61×1023 oxygen molecules at a temperature of 359. 0 k. what is the thermal energy of the gas? (you migh

t need to know boltzmann's constant: kb = 1. 38×10-23 j/k. )
Chemistry
1 answer:
Cloud [144]1 year ago
5 0

A gas bottle contains 8. 61×1023 oxygen molecules at a temperature of 359. 0 k then the thermal energy of the gas is 6.35KJ.

<h3>What is thermal energy? </h3>

Thermal energy is the energy contained within a system which is responsible for its temperature. Heat is also termed as flow of thermal energy.

Thermal energy is directly proportional to the temperature. As temperature increase thermal energy increases.

Given,

temperature = 395K

Number of oxygen molecules= 8.61 × 10^(23)

Firstly we will calculate the number of moles = N/A

where A is the avagadro number = 6.022 × 10^(23)

number of moles = 8.61 × 10^(23)/6.022 ×10^(23)

number of moles = 1.42moles

Using the energy equation,

E = 3/2 × nRT

where R is the gas constant = 8.314J/molK

E = 3/2 × 1.42 × 8.314 × 359

= 6357.4J

= 6.35KJ

Thus, we found that the thermal energy of the gas is 6.35KJ.

learn more about thermal energy:

brainly.com/question/2409175

#SPJ4

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Combustion analysis is performed on 0.50 g of a hydrocarbon, and 1.47 g of CO2 and 0.902 g of H2O are produced. What is the empi
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1. The empirical formula of the hydrocarbon is CH₃

2. The molecular formula of the hydrocarbon is C₂H₆

<h3>How to determine the mass of Carbon </h3>
  • Mass of CO₂ = 1.47 g
  • Molar mass of CO₂ = 44 g/mol
  • Molar of C = 12 g/mol
  • Mass of C =?

Mass of C = (12 / 44) × 1.47

Mass of C = 0.4 g

<h3>How to determine the mass of H</h3>
  • Mass of compound = 0.5 g
  • Mass of C = 0.4 g
  • Mass of H = ?

Mass of H = (mass of compound) – (mass of C)

Mass of H = 0.5 – 0.4

Mass of H =0.1 g

<h3>1. How to determine the empirical formula </h3>
  • C = 0.4 g
  • H = 0.1 g
  • Empirical formula =?

Divide by their molar mass

C = 0.4 / 12 = 0.03

H = 0.1 / 1 = 0.1

Divide by the smallest

C = 0.03 / 0.03 = 1

H = 0.1 / 0.03 = 3

Thus, the empirical formula of the compound is CH₃

<h3>2. How to determine the molecular formula</h3>
  • Empirical formula = CH₃
  • Molar mass = 30 g/mol
  • Molecular formula =?

Molecular formula = empirical × n = mass number

[CH₃]n = 30

[12 + (3×1)]n = 30

15n = 30

Divide both side by 15

n = 30 / 15

n = 2

Molecular formula = [CH₃]n

Molecular formula = [CH₃]₂

Molecular formula = C₂H₆

Learn more about empirical formula:

brainly.com/question/24297883

#SPJ1

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