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8090 [49]
4 years ago
15

A floor polisher has a rotating disk that has a 14-cm radius. The disk rotates at a constant angular velocity of 1.3 rev/s and i

s covered with a soft material that does the polishing. An operator holds the polisher in one place for 36 s, in order to buff an especially scuffed area of the floor. How far does a spot on the outer edge of the disk move during this time

Physics
2 answers:
luda_lava [24]4 years ago
6 0

Answer:

Distance moved = 41.2m

Explanation:

Detailed explanation and calculation is shown in the image below

erik [133]4 years ago
4 0

Answer:

d = 41.17 m

The outer edge of the disk moves 41.17m during this time

Explanation:

Given;

angular velocity w = 1.3 rev/s

Radius of rotating disc r = 14 cm = 0.14m

Time t = 36s

The linear velocity v can be derived using;

v = 2πwr

And the distance covered can be expressed as;

d = vt = 2πwrt

d = 2πwrt .......1

Where; w,t,r are angular velocity,time and radius respectively.

Substituting the given values into equation 1

d = 2π×1.3×0.14×36

d = 41.17 m

The outer edge of the disk moves 41.17m during this time

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Pls answer my quetion i will give brainlist answer​
allochka39001 [22]

Answer:

here's an explanation but not the answer

please kindly send No or Yes understand.

Explanation:

A 10-N force is applied to push a block across a friction free surface for a displacement of 5.0 m to the right.

See Answer

See Answer

A 10-N frictional force slows a moving block to a stop after a displacement of 5.0 m to the right.

7 0
3 years ago
Calculate the momentum, A bald eagle with a mass of 26.4 kg and velocity of 15.6 m/s​
AveGali [126]

Answer:

<u>411.84 kg m/s</u>

Explanation:

Formula :

<u>Momentum = mass × velocity</u>

<u />

=========================================================

Given :

⇒ mass = 26.4 kg

⇒ velocity = 15.6 m/s

=========================================================

Solving :

⇒ Momentum = 26.4 × 15.6

⇒ Momentum = <u>411.84 kg m/s</u>

3 0
2 years ago
A racing car travels with a constant tangential speed of 80.8 m/s around a circular track of radius 602 m. (a) Find the magnitud
KatRina [158]

Answer:

10.84 m/s2 radially inward

Explanation:

As the car is traveling an a constant tangential speed of 80.8 m/s, the total acceleration only consists of the centripetal acceleration and no linear acceleration. The formula for centripetal acceleration with respect to tangential speed v = 80.8 m/s and radius r =602 m is

a = \frac{v^2}{r} = \frac{80.8^2}{602} = 10.84 m/s^2

b) The direction of this centripetal acceleration is radially inward

6 0
4 years ago
Iron oxide reacts with aluminum to give aluminum oxide and iron. What kind of chemical reaction is this?
dexar [7]

a displacement reaction

5 0
3 years ago
In the Bohr model of the hydrogen atom, an electron orbits a proton in a circular orbit of radius 0.53 X 10^-10 m. What is elect
maxonik [38]

Answer:

a) 27.2 V

b)27.2 V

Explanation:

Charge of the electron =charge of the proton = q = 1.6 × 10⁻¹⁹ C

Radius = r = 0.53×10⁻¹⁰ m

Electric Potential = V = k q/r

k = 9 ×10⁹ N m²/C² = Coulomb's constant.

V = (9 ×10⁹)(1.6 × 10⁻¹⁹)/( 0.53×10⁻¹⁰) = 27.2 V

b) Potential Energy of the electron =  k q × q / r

   = [(9 ×10⁹)(1.6 × 10⁻¹⁹)(1.6 × 10⁻¹⁹) / (0.53×10⁻¹⁰)] / (1.6 × 10⁻¹⁹) eV,

since 1 electron volt = (1.6 × 10⁻¹⁹)joules

   = 27.2 eV

7 0
4 years ago
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