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RSB [31]
3 years ago
13

Can you help me please!!

Mathematics
1 answer:
ahrayia [7]3 years ago
8 0
I believe it would be 30

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14+6×(9-6)<br><br>please answer ​
Andreas93 [3]

Answer:

32

Step-by-step explanation:

14+6(9-6)

[9-6=3]

14+6x3

[6x3=18]

14+18

32

---

hope it helps

5 0
2 years ago
Read 2 more answers
Solve the inequality - 12 &gt; -16. Then graph the solution.
ozzi

Solve the inequality c - 12 > -16.

\begin{gathered} c-12>-16 \\ c-12+12>-16+12 \\ c>-4 \end{gathered}

Plot the solution on the number line.

7 0
1 year ago
Can u help me out ?!!
Art [367]
I’m sorry this is hard:.(
3 0
2 years ago
What does -1 mult. 2 mean?
Sonbull [250]

Answer:

-2

Step-by-step explanation:

-1 multiplied by 2

8 0
2 years ago
What are all the zeros of the equation x^4 -6x^2-7x-6=0
nasty-shy [4]

Answer:

-2,3 and \frac{-1±i\sqrt{3} }{2}

Step-by-step explanation:

Given is an equation of power 4 in polynomial as

x^4 -6x^2-7x-6=0

We have to find the zeroes of the funciton

By rational roots theorem since constant term = -6 and Leading coefficient =1

possible rational factors can be

±1,±2,±3,±6

By trial and error we try one by one.

f(3) =3^4 -6(3)^2-7(3)-6=0

So x=3 is zero and x-3 is factor

Try with -2

f(-2) =(-2)^4 -6(-2)^2-7(-2)-6\\=16-24+14-6=0

x=-2 is the zero

Now divide the given polynomial by (x+2)(x-3) to get quadratic form

Given polynomial = (x+2)(x-3)(x^2+x+1)

Find the roots of quadratic by formula

x=x=\frac{-1±\sqrt{1-4} }{2} \\=\frac{-1±i\sqrt{3} }{2}

So roots are -2,3 and \frac{-1±i\sqrt{3} }{2}

5 0
3 years ago
Read 2 more answers
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