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3 years ago

What is the value for AG at 100 Kif AH = 27 kJ/mol and AS = 0.09 kJ/(mol-K)?

Chemistry

1 answer:

Elina [12.6K]3 years ago

7 0

Answer:

ΔG = 18KJ/mol

Explanation:

Given data:

ΔS = 0.09 Kj/mol.K

ΔH = 27 KJ/mol

Temperature = 100 K

ΔG = ?

Solution:

Formula:

ΔG = ΔH - TΔS

ΔH = enthalpy

ΔS = entropy

by putting values,

ΔG = 27 KJ/mol - 100K(0.09 Kj/mol.K)

ΔG = 27 KJ/mol - 9 KJ/mol

ΔG = 18KJ/mol

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80 points!!

ikadub [295]

Materials: laser pointer/ flashlight with a paper with a small slit, glass prism

step 1.) turn on the laser pointer point it up to the ceiling.

step 2.) point to prism, explain how the light refracts in the prism. and how it changes.

(I hope this helps!)

6 0

3 years ago

Read 2 more answers

The enthalpy of combustion of n-octane, C8H18, is –4.79 × 107 J/kg. What is the enthalpy of combustion expressed in kJ/g?

SIZIF [17.4K]

Answer:

47,9 kJ/g

Explanation:

The enthalpy of combustion is the change in energy due the reaction of combustion of n-octane. If the enthalpy is -4,79x10⁷ J/kg And knowing (1000J = 1kJ) (1000g = 1kg). The enthalpy of combustion expressed in kJ/g is:

$-4,79x10^7J/kg \frac{1kJ}{1000J} \frac{1kg}{1000g}$ = 47,9kJ/g

I hope it helps!

6 0

4 years ago

Nitric oxide, an important pollutant in air, is formed from the elements nitrogen and oxygen at high temperatures, such as those

Tanya [424]

Answer:

Q is 0.5 and K is 0.01, therefore K is less than Q.

the system will proceed in the reverse direction, thereby converting products into reactants. converting Nitric oxide to form oxygen and nitrogen.

Explanation:

Given,

N2 (g) + O2 (g) « 2 NO (g)

K = 0.01

heated temperature = 2000 ⁰C

N2 moles =0.4

O2 moles =0.1

2NO moles = 0.08

Volume of container = 1L

Q is the reaction quotient of the equilibrium equation. it is use to determined which direction the system will move to by comparing it with the K value.

Q can be calculated by multiplication of mass of reactant divide by mass of product

Q = $\frac{ [N2] *[O2}{2NO}$

the mass of the chemicals are in mole, there is need to convert them to moles/litre

therefore,

for N₂ : 0.4 mole per 1L container = 0.4 mol/L = 0.4M

for O₂ : 0.1 mole per 1L container = 0.1 mol/L = 0.1M

for 2NO : 0.08mole per 1L container = 0.08 mol/L = 0.08M

Q = $\frac{ [N2] *[O2}{2NO}$ = (0.4*0.1)/0.08 = 0.5

finally, we are going to compare the value of Q with K

Note that:

if K>Q , the reaction will proceed forward, converting reactants into product.

if K<Q , the reaction will proceed backward, converting products into reactants.

if K=Q , the system of reaction is already in equilibrium.

since, Q is 0.5 and K is 0.01, therefore K is less than Q.

the system will proceed in the reverse direction, thereby converting products into reactants. converting Nitric oxide to form oxygen and nitrogen.

7 0

3 years ago

Which pair of atoms forms a nonpolar covalent bond? which pair of atoms forms a nonpolar covalent bond? na and cl c and o n and

adelina 88 [10]

Types of Bonds can be predicted by calculating the difference in electronegativity.

If, Electronegativity difference is,

Less than 0.4 then it is Non Polar Covalent

Between 0.4 and 1.7 then it is Polar Covalent

Greater than 1.7 then it is Ionic

For Na and Cl,

E.N of Chlorine = 3.16

E.N of Sodium = 0.93

________

E.N Difference 2.23 (Ionic Bond)

For C and O,

E.N of Oxygen = 3.44

E.N of Carbon = 2.55

________

E.N Difference 0.89 (Polar Covalent Bond)

For N and Cl,

E.N of Chlorine = 3.16

E.N of Notrogen = 3.04

________

E.N Difference 0.12 (Non-Polar Covalent Bond)

For B and O,

E.N of Oxygen = 3.44

E.N of Boron = 2.04

________

E.N Difference 1.40 (Polar Covalent Bond)

8 0

4 years ago

Read 2 more answers

Imagine two solutions with the same concentration and the same boiling point, but one has ethanol as the solvent and the other h

defon

Answer: m = 0.42; Tb = 79°

Explanation: The relationship between boiling point of the solvent above a solution is directly proportional to the molal concentration of the solute, i.e.:

ΔT = $K_{b}.m$

where

ΔT is the change in boiling point of the solvent;

$K_{b}$ is the molal boiling point elevation constant;

m is the molal concentration of the solute in the solution;

For there two solutions:

1) Ethanol:

ΔT = $K_{b}.m$

Tb - $T_{normal} = K_{b}.m$

Tb - 78.4 = 1.22.m (1)

2) Carbon Tetrachloride:

Tb - $T_{normal} = K_{b}.m$

Tb - 76.8 = 5.03.m (2)

Solving the system of equations:

Tb - 78.4 = 1.22.m

Tb = 1.22.m + 78.4 (3)

Substituing (3) in (2)

1.22.m + 78.4 - 76.8 = 5.03m

3.81m = 1.6

m = 0.42

With m, find Tb:

T - 76.8 = 5.03.0.42

T = 2.11 + 76.8

T = 79°

Molal concentration is 0.42 and boiling point is 79°

4 0

3 years ago