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3 years ago

What is the value for AG at 100 Kif AH = 27 kJ/mol and AS = 0.09 kJ/(mol-K)?

Chemistry

1 answer:

Elina [12.6K]3 years ago

7 0

Answer:

ΔG = 18KJ/mol

Explanation:

Given data:

ΔS = 0.09 Kj/mol.K

ΔH = 27 KJ/mol

Temperature = 100 K

ΔG = ?

Solution:

Formula:

ΔG = ΔH - TΔS

ΔH = enthalpy

ΔS = entropy

by putting values,

ΔG = 27 KJ/mol - 100K(0.09 Kj/mol.K)

ΔG = 27 KJ/mol - 9 KJ/mol

ΔG = 18KJ/mol

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svetoff [14.1K]

Answer:

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3 years ago

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Burka [1]

Answer:

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3 years ago

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likoan [24]

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Missing question:
Synthesis.
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3 years ago

What mass of solid sodium formate (of MW 68.01) must be added to 150 mL of 0.42 mol/L formic acid (HCOOH) to make a buffer solu-

Sergio [31]

Answer:

We need 4.28 grams of sodium formate

Explanation:

Step 1: Data given

MW of sodium formate = 68.01 g/mol

Volume of 0.42 mol/L formic acid = 150 mL = 0.150 L

pH = 3.74

Ka = 0.00018

Step 2: Calculate [base)

3.74 = -log(0.00018) + log [base]/[acid]

0 = log [base]/[acid]

0 = log [base] / 0.42

10^0 = 1 = [base]/0.42 M

[base] = 0.42 M

Step 3: Calculate moles of sodium formate:

Moles sodium formate = molarity * volume

Moles of sodium formate = 0.42 M * 0.150 L = 0.063 moles

Step 4: Calculate mass of sodium formate:

Mass sodium formate = moles sodium formate * Molar mass sodium formate

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Mass sodium formate = 4.28 grams

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3 years ago

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natita [175]

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3 years ago