3 years ago

HELP ASAP PLEASE!!!

Chemistry

1 answer:

Mashcka [7]3 years ago

3 0

I believe it’s false

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How many atoms of aluminum are in one formula unit of aluminum chloride?

ICE Princess25 [194]

The formula for aluminum fluoride is $AlF_{3}$

That means that there is 1 Aluminum and 3 fluorde ions in 1 molecule. The 3 does not effect the Aluminum at all.

The Answer is A

7 0

3 years ago

How many iron atoms contained in a 0.83 mole sample of iron

xxMikexx [17]

Answer: 5.00 x 10^23 atoms

Explanation:

Based on Avogadro's law:

1 mole of any substance has 6.02 x 10^23 atoms

So, 1 mole of Iron = 6.02 x 10^23 atoms

0.83 moles of Iron = Z atoms

To get the value of Z, cross multiply:

Z atoms x 1mole = (6.02 x 10^23 x 0.83)

Z = 5.00 x 10^23 atoms

Thus, there are 5.00 x 10^23 atoms of iron.

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3 years ago

For the following measurements , 27.5 x 0.125 x 13= 44.6875 , choose the answer that is rounded to the correct number of signifi

sergejj [24]

The Answer is C-44.7

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3 years ago

Which of the following statements is true? A)Unsaturated solutions will not dissolve more solute. B)For most substances, the sol

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B <span>For most substances, the solid state is more dense than the liquid state.</span>

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3 years ago

How many grams S03<br> are needed to make 400g<br> H₂So4 in 49%

NemiM [27]

160 g of SO3 are needed to make 400 g of 49% H2SO4.

<h3>How many grams of SO3 are required to prepare 400 g of 49% H2SO4?</h3>

The equation of the reaction for the formation of H2SO4 from SO3 is given below as follows:

$SO_{3} + H_{2}O \rightarrow H_{2}SO_{4}$

1 mole of SO3 produces 1 mole of H2SO4

Molar mass of SO3 = 80 g/mol

Molar mass of H2SO4 = 98 g/mol

80 g of SO3 are required to produce 98 og 100%H2SO4

mass of SO3 required to produce 400 g of 100 %H2SO4 = 80/98 × 400 = 326.5 g of SO3

Mass of SO3 required to produce 49% of 400 g H2SO4 = 326.5 × 49% = 160 g

Therefore, 160 g of SO3 are needed to make 400 g of 49% H2SO4.

Learn more about mass and moles at: brainly.com/question/15374113

#SPJ1

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2 years ago