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3 years ago

In the peptide GLVIW, the C-terminal end is ________.

1 answer:

5 0

The peptide given above is made up of the following amino acids: glycine [G], leucine [L], valine [V], isoleucine [I] and tryptophan [W]. These amino acids are joined together by amide bond to form peptide. Peptides usually have two terminals, the N terminal and the C terminal. For GLVIW, the C terminal end amino acid is tryptophan, that is the last amino acid on the peptide chain. The N terminal amino acid is glycine, that is, the first amino acid on the peptide chain.

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Conversion of minus 1 coulomb meter in debye

Viktor [21]

Answer:

-1 Coulomb meter = -2.997 × 10²⁹ Debye

Explanation:

Given:

Coulomb meter = -1 CM

Find:

In debye

Computation:

We know that,

1 Coulomb meter = 299,792,458,178,090,000,000,000,000,000 Debye

So,

-1 Coulomb meter = -299,792,458,178,090,000,000,000,000,000 Debye

-1 Coulomb meter = -2.997 × 10²⁹ Debye

3 0

3 years ago

Calculate the molar solubility of CaF2 at 25°C in a solution that is 0.010 M in Ca(NO3)2. The Ksp for CaF2 is 3.9 x 10-11.

madreJ [45]

Answer:

$Molar \ solubility=3.12x10^{-5}M$

Explanation:

Hello,

In this case, for the dissociation of calcium fluoride:

$CaF_2(s)\rightleftharpoons Ca^{2+}+2F^-$

The equilibrium expression is:

$Ksp=[Ca^{2+}][F^-]^2$

In such a way, via the ICE procedure, including an initial concentration of calcium of 0.01 M (due to the calcium nitrate solution), the reaction extent $x$ is computed as follows:

$3.9x10^{-11}=(0.01+x)(2*x)^2\\\\x=0.0000312M$

Thus, the molar solubility equals the reaction extent $x$ , therefore:

$Molar \ solubility=3.12x10^{-5}M$

Regards.

4 0

3 years ago

Consider the equilibrium reaction. 2 A + B − ⇀ ↽ − 4 C After multiplying the reaction by a factor of 2, what is the new equilibr

vredina [299]

Answer : The correct expression for equilibrium constant will be:

$K_c=\frac{[C]^8}{[A]^4[B]^2}$

Explanation :

Equilibrium constant : It is defined as the equilibrium constant. It is defined as the ratio of concentration of products to the concentration of reactants.

The equilibrium expression for the reaction is determined by multiplying the concentrations of products and divided by the concentrations of the reactants and each concentration is raised to the power that is equal to the coefficient in the balanced reaction.

As we know that the concentrations of pure solids and liquids are constant that is they do not change. Thus, they are not included in the equilibrium expression.

The given equilibrium reaction is,

$4A+2B\rightleftharpoons 8C$

The expression of $K_c$ will be,

$K_c=\frac{[C]^8}{[A]^4[B]^2}$

Therefore, the correct expression for equilibrium constant will be, $K_c=\frac{[C]^8}{[A]^4[B]^2}$

4 0

3 years ago

What type of bond is present between two atoms of tungsten in a light bulb filament?

stiks02 [169]

Answer:

ionic bonding

Explanation:

hope it helps

8 0

3 years ago

How many nitrogen atoms are represented in 2Ca(NO3)2?

arsen [322]

Explanation:

there is 2 nitrogen but if you mean nitrate is 6

4 0

3 years ago