<h2><u>Q</u><u>u</u><u>e</u><u>s</u><u>t</u><u>i</u><u>o</u><u>n</u>:-</h2>
The speed of a wave is 40 m/s. If the wavelength is 80 centimeters, what is the frequency of the wave ?
<h2><u>A</u><u>n</u><u>s</u><u>w</u><u>e</u><u>r</u>:-</h2>
<h3>Given:-</h3>
Velocity (V) = 40 m/s
Wavelength
= 80 cm = 0.8 m
<h3>To Find:-</h3>
The frequency (F) of the wave.
<h2>Solution:-</h2>
We know,

40 = F × 0.8
F = 
F = 50
<h3>The frequency of the wave is <u>5</u><u>0</u><u> </u><u>H</u><u>z</u>. [Answer]</h3>
Answer:
<em>The total time is: t=451.22 sec</em>
<em>The average speed is: V=34.57 m/s</em>
Explanation:
<u>Average speed</u>
The average speed is calculated by dividing the total distance traveled by an object (x) by the total time it took it to travel that distance (t).

Since the student makes the trip in two parts, we have to calculate the total distance and the total time.
We know the distance to school is 7.8 Km = 7,800 m. The student makes his way home over the same distance, thus the total distance is
x=2*7,800 m=15,600 m
The first trip to school was done at an average speed of v1=32.6 m/s. Knowing the distance and speed, we can calculate the time:

The second trip back home was done at an average speed of v2=36.8 m/s. Let's calculate the second time:

The total time is:


The average speed is:


Answer:
temperature
Explanation:
when you put a water on the stove the water will start to boil there for temperature
Answer:
Z = R, i = V/Z, w = √1 / LC
Explanation:
In an RLC circuit the impedance of the circuit is
Z = √[R² + (
)²
Where
= wL
X_{L} = 1 / wC
They are the reactances of the inductor and the capacitor, in this case the current advances to the voltage in the first and is delayed from the voltage in the second, so when the two values give the same reactance the current goes in phase with the voltage and the impedance is minimal
Z = R
V= i Z
i = V/Z
Therefore the current is maximum, this occurs when
w = √1 / LC
Saying that this is the resonant frequency
Answer:
Power = 30 [watts]
Explanation:
Initia data:
F = force = 30[N]
d = displacement = 2 [m]
By definition we know that work is equal to the product of force by the distance displaced
Therefore:
W = F * d = 30 * 2
W = 60 [J]
And power is defined as the amount of work done in a given time interval
time = t = 2 [sec]
Power = W / t
Power = 60 / 2
Power = 30 [W]