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3 years ago

9

How does a network solid differ from most other covalent compounds

1 answer:

blondinia [14]3 years ago

5 0

Answer:

Covalent compounds are held by intermolecular forces while network solids are held by strong bonds in unit cells which are closely packed together.

Explanation:

Covalent compound molecules are held by vanderwaals forces which are relatively weak but strong enough to hold some covalent molecules together in the solid state. However, network solids contain atom to atom covalent bonds arranged in an orderly manner and regular repeating unit cells to form a rigid three dimensional network solid.

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Calculate the amount of heat water absorbs from a piece of hot metal using the following data: 75.0 g of cold water is placed in

AysviL [449]

Answer:

Amount of heat absorbed by water is 2604.54 J.

Explanation:

Amount of heat absorbed by water = $m_{water}\times C_{water}\times \Delta T_{water}$

where m represents mass, C represents specific heat and $\Delta T$ represents change in temperature.

Here $m_{water}=75.0$ g , $C_{water}=4.184J/(g.^{0}\textrm{C})$ and $\Delta T$ = (final temperature - initial temperature) = (29.5-21.2) $^{0}\textrm{C}$ = 8.3 $^{0}\textrm{C}$

So, amount of heat heat absorbed by water

= $(75.0g)\times (4.184\frac{J}{g.^{0}\textrm{C}})\times (8.3^{0}\textrm{C})$

= 2604.54 J

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3 years ago

Which is NOT a way that Carbon is released in to the atmosphere?

amid [387]

Answer:

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Explanation:

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2 years ago

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A compound with the empirical formula CH 2 O has a formula mass of 180 g/mol. What is its molecular formula

olga nikolaevna [1]

Empirical formula mass

12+2(1)+16
28+2
30g/mol

Molecular fornula mass:-180g/mol

n=Molecular formula mass/Empirical formula mass
m=180/30
n=6

Molecular formula:-

n×Empirical formula
6(CH_2O
C_6H_12 O_6

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2 years ago

The amount of space tgat matter occupies is referred to as...

Marrrta [24]

It is either mass or volume

4 0

2 years ago

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The decomposition of N2O to N2 and O2 is a first-order reaction. At 730°C, the rate constant of the reaction is 1.94 × 10-4 min-

grin007 [14]

Answer:

Total pressure 5.875 atm

Explanation:

The equation for above decomposition is

$2N_2O \rightarrow 2N_2 + O_2$

rate constant $k = 1.94\times 10^{-4} min^{-1}$

Half life $t_{1/2} = \frac{0.693}{k} = 3572 min$

Initial pressure $N_2 O = 4.70 atm$

Pressure after 3572 min = P

According to first order kinematics

$k = \frac{1}{t} ln\frac{4.70}{P}$

$1.94\times 10^{-4} = \frac{1}{3572} \frac{4.70}{P}$

solving for P we get

P = 2.35 atm

$2N_2O \rightarrow 2N_2 + O_2$

initial 4.70 0 0

change -2x +2x +x

final 4.70 -2x 2x x

pressure of $O_2$ after first half life = 2.35 = 4.70 - 2x

x = 1.175

pressure of $N_2$ after first half life = 2x = 2(1.175) = 2.35 ATM

Total pressure = 2.35 + 2.35 + 1.175

= 5.875 atm

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3 years ago

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