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sleet_krkn [62]
3 years ago
14

A boy swings a rubber ball attached to a string over his head in a horizontal, circular path. The piece of string is 1.15 m long

and the ball makes 137 complete turns each minute. What is the tangential velocity of the ball
Chemistry
1 answer:
gregori [183]3 years ago
5 0

Answer:

v = 16.49 m/s

Explanation:

Given that,

Length of the string, l = 1.15 m

The ball makes 137 complete turns each minute.

We know that, 1 turn = 6.28 rad

137 turns = 860.79 rad

1 min = 60 s

\omega=\dfrac{860.79\ rad}{60\ s}\\\\=14.34\ rad/s

We need to find the tangential velocity of the ball. It can be given by

v=r\omega\\\\=1.15\times 14.34\\\\v=16.49\ m/s

So, the tangential velocity of the ball is 16.49 m/s.

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Alex787 [66]
The answer:
for the monoatomic <span>selenium ions
</span>    -the ion charge of selenium is 2-, so the answer is [Se]2+ 
as for the monoatomic phosphorus ions
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6 0
3 years ago
an engineer wishes to design a container that will hold 12.0 mol of ethane at a pressure no greater than 5.00x10*2 kPa and a tem
OleMash [197]

Answer:

The minimum volume of the container is 0.0649 cubic meters, which is the same as 64.9 liters.

Explanation:

Assume that ethane behaves as an ideal gas under these conditions.

By the ideal gas law,

P\cdot V = n\cdot R\cdot T,

\displaystyle V = \frac{n\cdot R\cdot T}{P}.

where

  • P is the pressure of the gas,
  • V is the volume of the gas,
  • n is the number of moles of particles in this gas,
  • R is the ideal gas constant, and
  • T is the absolute temperature of the gas (in degrees Kelvins.)

The numerical value of R will be 8.314 if P, V, and T are in SI units. Convert these values to SI units:

  • P =\rm 5.00\times 10^{2}\;kPa = 5.00\times 10^{2}\times 10^{3}\; Pa = 5.00\times 10^{5}\; Pa;
  • V shall be in cubic meters, \rm m^{3};
  • T = \rm 52.0 \textdegree C = (52.0 + 273.15)\; K = 325.15\; K.

Apply the ideal gas law:

\displaystyle \begin{aligned}V &= \frac{n\cdot R\cdot T}{P}\\ &= \frac{12.0\times 8.314\times 325.15}{5.00\times 10^{5}}\\ &= \rm 0.0649\; m^{3} \\ &= \rm (0.0649\times 10^{3})\; L \\ &=\rm 64.9\; L\end{aligned}.

4 0
3 years ago
Which best explains why ionization energy tends to decrease from the top to the bottom of a group?
Setler79 [48]

Answer:

Electrons are far apart from the nucleus as we move down the group.

Explanation:

The ionization energy is the amount of energy which is necessary to remove an electron from an atom.

In an atom there exist a force of attraction at the center (nucleus). This is because of the positive charge which exists in the nucleus. This force of attraction is less felt as the distance between the electron and the proton increases. Hence the ionization energy increases as the number of shells increases for an atom. As we move down the group in the periodic table, the number of shells increases which implies a decrease in ionization energy.

5 0
3 years ago
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To determine the concentration of X in an unknown solution, 1.00 mL of 8.48 mM S was added to 3.00 mL of the unknown X solution
kogti [31]

Answer:

positif

Explanation:

3.87169.843826 = y = x = .ion \: in \: cells = y = x. >  \\  \geqslant  {8}^{2}  \times \frac{4}{3}  | \geqslant |  \times \frac{68.1 < }{3 = 8}

6 0
3 years ago
The ionization constant for water (kw) is 9.311 × 10−14 at 60 °c. calculate [h3o+], [oh−], ph, and poh for pure water at 60 °c.
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As,

Kw = [H+] [OH-]

For water, [H+] = [OH-]

Therefore we can write

Kw = [H+]²

9.311 × 10-14 = [H+]²

[H+] = 3.04 × 10-7 = [OH-]

Ph = - log [H+]

= - log ( 3.04 × 10-7)

= 6.52

Thus, Ph = PoH = 6.52

5 0
3 years ago
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