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Nataly [62]
3 years ago
14

Ryan wants to identify an element. Which piece of information would best help Ryan identify the element?

Physics
2 answers:
xxMikexx [17]3 years ago
8 0
The number of protons it has.
butalik [34]3 years ago
4 0

Answer: How many protons the element has

Explanation: The atoms of each element differ from those of all other elements in the number of protons. If Ryan found out how many protons the element had, he would be able to identify the element.

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Infectious Disease Specialist?

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A U-shaped tube, open to the air on both ends, contains mercury. Water is poured into the left arm until the water column is 10.
Masja [62]

Answer:

0.368 cm

Explanation:

x = distance by which the mercury rise

d = depth of the water = 10 cm = 0.10 m

ρ = density of water = 1000 kgm⁻³

ρ' = density of mercury = 13600 kgm⁻³

P₀ = atmospheric pressure

Using equilibrium of pressure on both side

P₀ + ρ g d = P₀ + ρ' g (2x)

(1000) (0.10) = (13600) (2x)

x = 0.00368 m

x = 0.368 cm

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2 years ago
What is an equilibrant?
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<span>The equilibrant, also known as the counterbalancer in a force system, is an equal but opposite force that produces equilibrium. It acts against the resultant force to keep a body motionless. Suppose we have a 20kg mass on one end of a swing and nothing on the other. The swing will be titled unevenly because no force balances the 20kg weight. On the other hand suppose a weight of 40kg rest on the other end. This force doesn't produce equilibrium either because it isn't equal to the 20kg weight; the swing would tilt towards the weight of larger mass. A 20kg mass will balance the system. Hence the force which balances other forces, thus bringing an object to equilibrium is the equilbrant.</span>
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- The Grayprational Force<br>with which the earth aracts<br>а,​
Fudgin [204]

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gravitational?

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5 0
3 years ago
A signal is sampled at 10000 Hz and a total of 1024 data samples are taken, what are the highest and lowest frequencies that can
tia_tia [17]

Since the discrete Fourier series, the Sampling rate, would be the equivalent of the inverse of the passage of time, that is, to the frequency, mathematically this can be written as,

\frac{1}{\Delta t} = 10000Hz

In turn, the time can be described depending on the period and the amount of data samples taken. This would be,

\Delta t = \frac{T}{m}

Here,

m = Data Samples

T = Period

Replacing,

\Delta t = \frac{T}{1024}

Replacing the value of the time from the first equation,

\frac{1024}{T} = 10000

T = 102.4ms

At the same time, the range then will be given between the basic frequency to the half of the sample, that is,

f_{min} = \frac{1}{T} = 9.165Hz

f_{max} = \frac{1024}{2} (9.165Hz)

f_{max} = 5000Hz

Therefore the lowest frequency is 5000Hz and highest 9.165Hz

7 0
3 years ago
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