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MaRussiya [10]
3 years ago
13

Which applications, either for diagnostic purposes or for therapeutic purposes, involve radioactive materials placed in the body

? Check all that apply.
radiopharmaceuticals
MRI
laser eye surgery
external beam radiation therapy
lithotripsy
brachytherapy
radioisotope imaging
Physics
2 answers:
CaHeK987 [17]3 years ago
5 0

When a radioactive material is required to be placed in the body, the applications are brachytherapy and radioisotope imaging.

Radioactive materials are elements which has the ability to disintegrate by emitting radioactive substance or radiation. A good example of this is Cobalt-60, Titanium-99 etc.

Brachytherapy is a therapeutic process in which radioactive material is inserted into the body in close proximity to the region affected. The radioactive material emits radiations which are required to control the unwanted biological material in the body. A good application of this is the treatment of cancer using Cobalt-60.

Radioisotope imaging is a diagnostic process which is an imaging technique that may require placing a radioactive material in the body so as to trace or locate the affected part of the body. In this case, the material is used as a tracing element.

The applications that require the placing of radioactive materials in the body are brachytherapy and radioisotope imaging.

For more explanation, visit: brainly.com/question/9790340

vitfil [10]3 years ago
3 0

Answer:

radiopharmaceuticals

brachytherapy

radioisotope imaging

Explanation:

edge 2020

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Propose a hypothesis for how the position of the ball will affect the amount of its gravitational pull energy
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4 0
3 years ago
A golf ball is struck with a five iron on level ground. it lands 100.0 m away 4.60 s later. what was the magnitude and direction
finlep [7]

consider the motion in x-direction

v_{ox} = initial velocity in x-direction = ?

X = horizontal distance traveled = 100 m

a_{x} = acceleration along x-direction = 0 m/s²

t = time of travel = 4.60 sec

Using the equation

X = v_{ox} t + (0.5) a_{x} t²

100 =  v_{ox} (4.60)

v_{ox} = 21.7 m/s


consider the motion along y-direction

v_{oy} = initial velocity in y-direction = ?

Y = vertical displacement  = 0 m

a_{y} = acceleration along x-direction = - 9.8 m/s²

t = time of travel = 4.60 sec

Using the equation

Y = v_{oy} t + (0.5) a_{y} t²

0 = v_{oy} (4.60) + (0.5) (- 9.8) (4.60)²

v_{oy} = 22.54 m/s

initial velocity is given as

v_{o} = sqrt((v_{ox})² + (v_{oy})²)

v_{o} = sqrt((21.7)² + (22.54)²) = 31.3 m/s

direction: θ = tan⁻¹(22.54/21.7) = 46.12 deg

6 0
3 years ago
If you double the velocity of a moving object, how is it's momentum affected?
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If I weighed 50kg and I was jogging at 3m/s then I broke into a run at 6m/s how will me momentum be affected?
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6m/s*50kg=300

So as you can see by doubling the velocity you also double the momentum
8 0
3 years ago
A 1.5m wire carries a 8A current when a potential difference of 67v is applied what is the resistance of the wire
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Data is inappropriate

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            where R= resistance ; Ω

                       l = length of wire ; m

                       A = area of wire ; m²

                       ρ = resistivity ; Ω-m

But in general ohms law is

                    V = I R

                    R = V/I ;

but here we also calculate "R" from length of wire in which the current is flowing.

I hope it is helpful to you.

8 0
3 years ago
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