A 45 kg wagon is being pulled with a rope that makes an angle of 38 degrees with the horizontal. The applied force is 410 N and
1 answer:
Answer:
7.35m/s²
Explanation:
From the question we are not told what to find but we can as well find the acceleration of the wagon.
According to newton second law of motion
Fm is the moving force = 410N
is the coefficient of friction = 0.18
m is the mass = 45kg
g is the acceleration dur to gravity = 9.8m/s²
a is the acceleration of the wagon
Substitute the given data into the equation ang get ax
Hence the acceleration of the wagon is 7.35m/s²
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Answer:
F = 3.86 x 10⁻⁶ N
Explanation:
First, we will find the distance between the two particles:
where,
r = distance between the particles = ?
(x₁, y₁, z₁) = (2, 5, 1)
(x₂, y₂, z₂) = (3, 2, 3)
Therefore,
Now, we will calculate the magnitude of the force between the charges by using Coulomb's Law:
where,
F = magnitude of force = ?
k = Coulomb's Constant = 9 x 10⁹ Nm²/C²
q₁ = magnitude of first charge = 2 x 10⁻⁸ C
q₂ = magnitude of second charge = 3 x 10⁻⁷ C
r = distance between the charges = 3.741 m
Therefore,
<u>F = 3.86 x 10⁻⁶ N</u>