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tigry1 [53]
3 years ago
8

I want ti know how to study​

Physics
2 answers:
loris [4]3 years ago
5 0

Answer:

There are tons of different ways to study.

Explanation:

If unclear on a subject, or you just want to try to get a good grade on a test that is coming up, it would be helpful to study.  Find good ways that YOU like to study.

1rst you want to find your style. EX: If you are a logical learner, study maps are helpful.

One good way is to review your notes. Sometimes i do not like reveiwing my notes if they have messy handwriting, or just look bad, so you might want to make your notes look fun and pretty. After you have studied your notes, ask yourself some questions about the subject you would imagine your teacher asking.

Another way is flashcards. You can get some cool flashcard and info from this cool website called quizlet.

Also, you NEED breaks. If you study for more than 2 hours, you might get a lack of motivation and burnout.

So if you want to study for 30 mins take a 5-10 min break and then keep going

If you are reading a book and are trying to go fast, but still understand, read the first sentence of every paragraph, because those are like topic sentences.

When studying, pretend you are going to teach the material afterwords "If you can teach it, you know you have done right."

arlik [135]3 years ago
3 0

Answer:

Make sure everything is organized have a planner it can help

Get rid of all distractions

Listen to music if it helps you concentrate

Have your notes

Being willing to stay focus on what you are doing

Understand what you are doing

And most off all Be Happy and Remain Calm : )

You might be interested in
14. a ball is thrown horizontally from the roof of a building 75 m tall with a speed of 4.6 m/s. a. how much later does the ball
Burka [1]

The time taken to hit the ground is 3.9 s, the range is 18m and the final velocity is 42.82 m/s

<h3>Motion Under Gravity</h3>

The motion of an object under gravity is the vertical motion of the object under the influence of acceleration due to gravity.

Given that a ball is thrown horizontally from the roof of a building 75 m tall with a speed of 4.6 m/s.

a. how much later does the ball hit the ground?

The time can be calculated by considering the vertical component of the motion with the use of formula below.

h = ut + 1/2gt²

Where

  • Height h = 75 m
  • Initial velocity u = 0 ( vertical velocity )
  • Acceleration due to gravity g = 9.8 m/s²
  • Time t = ?

Substitute all the parameters into the formula

75 = 0 + 1/2 × 9.8 × t²

75 = 4.9t²

t² = 75/4.9

t² = 15.30

t = √15.3

t = 3.9 s

b. how far from the building will it land?

The range can be found by using the formula

R = ut

Where u = 4.6 m/s ( horizontal velocity )

R = 4.6 × 3.9

R = 18 m

c. what is the velocity of the ball just before it hits the ground?

The final velocity will be

v = u + gt

v = 4.6 + 9.8 × 3.9

v = 4.6 + 38.22

v = 42.82 m/s

Therefore, the answers are 3.9 s, 18 m and 42.82 m/s

Learn more about Vertical motion here: brainly.com/question/24230984

#SPJ1

7 0
1 year ago
Betty hits a baseball.
lorasvet [3.4K]

Answer:

point 2

Explanation:

5 0
3 years ago
What are some examples of irreversible processes in nature?
castortr0y [4]

Answer:

Burning. When you burn something, it turns into ash you can't make that thing turn into what it was before.

8 0
3 years ago
How much thermal energy is required to raise the temperature of 5 kg of water 50℃? The specific heat of water is 4168 J/kg*C.
sasho [114]

Answer/solution:

Given :

Mass =5kg

T 1 =20 C,T 2  =100 ∘C

ΔT=100−20=80 ∘C

Q=m×C×ΔT

where C= specific heat capacity of water

=4200J/(kgK)

Q=5×4200×80

=1680000 Joule.

=1680KJ

3 0
2 years ago
A Carnot engine operates between 1350 °F and 125 °F. If it rejects 55 Btu as heat, determine the work output.
ruslelena [56]

Answer:

C. W = 115.12\,Btu

Explanation:

Thermodynamically speaking, a Carnot engine represents an entirely reversible thermal process and its energy efficiency represents the maximum theoretical efficiency that thermal machines can reach. The efficiency of the ideal thermal process (\eta), no unit, is:

\eta = \left(1-\frac{T_{L}}{T_{H}} \right) (1)

Where:

T_{L} - Temperature of the cold reservoir, measured in Rankine.

T_{H} - Temperature of the hot reservoir, measured in Rankine.

If we know that T_{H} = 1809.67\,R and T_{L} = 584.67\,R, then the energy efficiency of the ideal thermal process is:

\eta = 0.678

By First Law of Thermodynamics, we calculate the work output:

W = Q_{H}-Q_{L}

W = \frac{W}{\eta} -Q_{L} (By definition of efficiency)

Q_{L} = \frac{W}{\eta}-W

Q_{L} = \left(\frac{1}{\eta}-1 \right)\cdot W(2)

Where:

Q_{H} - Heat received by the engine, measured in Btu.

Q_{L} - Heat rejected by the engine, measured in Btu.

W - Work output, measured in Btu.

If we know that \eta = 0.678 and Q_{L} = 55\,Btu, then the work output of the Carnot engine is:

W = \frac{Q_{L}}{\frac{1}{\eta}-1 }

W = 115.807\,Btu

The work output of the Carnot engine is 115.807 Btu. (Answer: C)

5 0
3 years ago
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