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tigry1 [53]
4 years ago
8

I want ti know how to study​

Physics
2 answers:
loris [4]4 years ago
5 0

Answer:

There are tons of different ways to study.

Explanation:

If unclear on a subject, or you just want to try to get a good grade on a test that is coming up, it would be helpful to study.  Find good ways that YOU like to study.

1rst you want to find your style. EX: If you are a logical learner, study maps are helpful.

One good way is to review your notes. Sometimes i do not like reveiwing my notes if they have messy handwriting, or just look bad, so you might want to make your notes look fun and pretty. After you have studied your notes, ask yourself some questions about the subject you would imagine your teacher asking.

Another way is flashcards. You can get some cool flashcard and info from this cool website called quizlet.

Also, you NEED breaks. If you study for more than 2 hours, you might get a lack of motivation and burnout.

So if you want to study for 30 mins take a 5-10 min break and then keep going

If you are reading a book and are trying to go fast, but still understand, read the first sentence of every paragraph, because those are like topic sentences.

When studying, pretend you are going to teach the material afterwords "If you can teach it, you know you have done right."

arlik [135]4 years ago
3 0

Answer:

Make sure everything is organized have a planner it can help

Get rid of all distractions

Listen to music if it helps you concentrate

Have your notes

Being willing to stay focus on what you are doing

Understand what you are doing

And most off all Be Happy and Remain Calm : )

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A physicist is constructing a solenoid. She has a roll of insulated copper wire and a power supply. She winds a single layer of
Leni [432]

Answer:

P =105.44 W

Explanation:

Given that

D= 10 cm ,L= 60 cm

d= 0.1 cm ,B= 6.4 mT

ρ= 1.7 x 10⁻⁸ Ω · m

The number of turns N

N= L/d

N= 60/0.1 = 600 turns

Length of wire

Lc= πDN

Lc= 3.14 x 0.1 x 600

Lc=188.4 m

The magnetic filed given as

B=\dfrac{\mu_oNI}{L}

I=\dfrac{BL}{\mu_oN}

Now by putting the values

I=\dfrac{0.0064\times 0.6}{4\pi \times 10^{-7}\times 600}

I=5.09 A

The resistance R given as

R=\dfrac{\rho L_c}{A}

A=\dfrac{\pi}{4}\times d^2

A=\dfrac{\pi}{4}\times (0.1\times 10^{-2})^2

R=\dfrac{1.7\times 10^{-8} \times 188.4}{\dfrac{\pi}{4}\times (0.1\times 10^{-2})^2}

R=4.07 Ω

Power P

p =I²R

P= 5.09² x 4.07 W

P =105.44 W

5 0
3 years ago
What is the Orbital Notation for Radon
balu736 [363]

I uploaded the answer to a file hosting. Here's link:

tinyurl.com/wpazsebu

4 0
3 years ago
A 12-volt car battery uses about 660 amps. How much power does it use?
alexira [117]
We know, Power = Voltage * Current
P = 660 * 12 = 7920 watt

In short, Your Answer would be Option A

Hope this helps!
8 0
4 years ago
Read 2 more answers
A 4.00-m long rod is hinged at one end. The rod is initially held in the horizontal position, and then released as the free end
Natalka [10]

Answer:

The angular acceleration α = 14.7 rad/s²

Explanation:

The torque on the rod τ = Iα where I = moment of inertia of rod = mL²/12 where m =mass of rod  and L = length of rod = 4.00 m. α = angular acceleration of rod

Also, τ = Wr where W = weight of rod = mg and r = center of mass of rod = L/2.

So Iα = Wr

Substituting the value of the variables, we have

mL²α/12 = mgL/2

Simplifying by dividing through by mL, we have

mL²α/12mL = mgL/2mL

Lα/12 = g/2

multiplying both sides by 12, we have

Lα/12 × 12 = g/2 × 12

αL = 6g

α = 6g/L

α = 6 × 9.8 m/s² ÷ 4.00 m

α = 58.8 m/s² ÷ 4.00 m

α = 14.7 rad/s²

So, the angular acceleration α = 14.7 rad/s²

5 0
3 years ago
The index of refraction of silicate flint glass for red light is 1.620 and for violet light is 1.660 . A beam of white light in
chubhunter [2.5K]

Answer:

The angular separation equals 0.35^{o}

Explanation:

We have according to Snell's law

n_{1}sin(\theta _{1})=n_{2}sin(\theta _{2})

\therefore \theta _{2}=sin^{-1}(\frac{n_{1}sin(\theta _{1})}{n_{2}})

Using this equation for both the colors separately we have

\theta _{red}=sin^{-1}(\frac{sin(23.90^{o})}{1.62})\\\\\theta _{red}=14.48^{o}

Similarly for violet light we have

\theta _{violet}=sin^{-1}(\frac{sin(23.90^{o})}{1.660})\\\\\theta _{violet}=14.13^{o}

Thus the angular separation becomes

\Delta \theta =14.48-14.13=0.35^{o}

6 0
4 years ago
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