Answer:
I cant fit the entire picture but this should help
The spring constant is 
Explanation:
For an object in a simple harmonic motion, the acceleration of the object is related to the displacement by

where
a is the acceleration
is the angular frequency
x is the displacement
The angular frequency is defined as

where
k is the spring constant
m is the mass
Substituting the second equation into the first one, we get

In this problem we have
m = 1 g = 0.001 kg
And at t=0,
x = 43.75 cm
a = -1.754 cm/s
Therefore, we can re-arrange the equation above to find the spring constant:

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Based on the trend produced by the dose - response graph, it would be best to evacuate the residents in other to prevent the increasing percentage of deaths due to the rising level of pollutant A.
- The curve shows that the pollutant level in mg/kg of pollutant A is still increasing, hence, groundwater monitoring alone won't be the best decision to make.
- Since the pollutant level is still increasing, then the spill level still need effective monitoring.
- Evacuation of residents seems to be the best decision that should be taken based on the information interpreted on the graph.
Therefore, Evacuating residents to prevent rising death percentage is required as the pollutant level is yet to subside.
Learn more :brainly.com/question/24844489
Explanation:
The runner was 8.6km away from the finish line when the bird starts flying.
Therefore it takes the bird 8.6/14.4 = 0.60 hours for the bird to fly to the finish line.
In that 0.60 hours, the runner would have ran an extra 3.6km/h * 0.6h = 2.16km.
Now, the runner and the bird are flying towards each other. The distance between them is 8.6 - 2.16 = 6.44km and their combined speed is 18.0km.
Hence, they will meet in 6.44/18.0 = 0.36 hours.
Overall, the bird flew for 0.60 + 0.36 = 0.96 hours, and flew 14.4km/h * 0.96h = 13.8km.
Answer:
The speed of space station floor is 49.49 m/s.
Explanation:
Given that,
Mass of astronaut = 56 kg
Radius = 250 m
We need to calculate the speed of space station floor
Using centripetal force and newton's second law




Where, v = speed of space station floor
r = radius
g = acceleration due to gravity
Put the value into the formula


Hence, The speed of space station floor is 49.49 m/s.