Complete Question
A person throws a pumpkin at a horizontal speed of 4.0 m/s off a cliff. The pumpkin travels 9.5m horizontally before it hits the ground. We can ignore air resistance.What is the pumpkin's vertical displacement during the throw? What is the pumpkin's vertical velocity when it hits the ground?
Answer:
The pumpkin's vertical displacement is 
The pumpkin's vertical velocity when it hits the ground is 
Explanation:
From the question we are told that
The horizontal speed is 
The horizontal distance traveled is 
The horizontal distance traveled is mathematically represented as
Where t is the time taken
substituting values
=> 
Now the vertical displacement is mathematically represented as
now the vertical velocity before the throw is zero
So
Now the final vertical velocity is mathematically represented as
substituting values
Answer:
Answer is in the following attachment.
Explanation:
The process of refraction of light occurs when light rays bends when travelling between media of different densities.
What is refraction of light?
Refraction of light is the bending of light rays or the change in the direction of light rays as it travels between media of different densities.
Light waves travel faster in media of less density than media of more density.
The change in density of the media makes light waves to be bend towards or away from the normal.
For example, when light travels from less dense air to more dense water, the light rays are bent towards the normal. However, when light rays travel from water to air, the light rays are refracted away from the normal.
In conclusion, refraction of light waves occur when light crosses the boundary of media of different densities.
Learn more about refraction of light at: brainly.com/question/27932095
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Answer:
J = 1800 kg-m/s
Explanation:
Given that,
Mass of a boy, m = 150 kg
Initial velocity of a boy, u = 12 m/s
Finally, it stops, v = 0
We need to find the impulse is required to produce this change in momentum. We know that impulse is equal to the change in momentum. So,
So, the impulse is equal to 1800 kg-m/s
