Answer:
70
Step-by-step explanation:
It is just
19²+π=1,133.54
The combinations of ordered triplets that are possible is equal to: A. 18.
<h3>How to find the possible number of ordered triplet?</h3>
Since the common difference (d) between the consecutive terms in an arithmetic progression (AP) is constant, we have:
d = y - x = z - y
Rearranging the terms, we have:
x = y - d
z = y + d
From the given equation:
x + y + z = 30
y - d + y + y + d = 30
3y = 30
y = 30/3
y = 10.
So the arithmetic progression (AP) is given by:
(10 - d), 10, (10 + d)....
Since the common difference (d) is a natural number which would be from 1 to 9, the combinations of ordered triplets that are possible is as follows:
Number of possibilities = 9 × 2
Number of possibilities = 18.
Read more on arithmetic progression here: brainly.com/question/18828482
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<u>Complete Question:</u>
If x, y, z are three natural numbers in A.P. such that x + y + z = 30 then the possible number of ordered triplet (x, y, z) is?
A. 18
B. 19
C. 20
D. 21
Hey there!
<h3>Distribute
into all of your terms! (MULTIPLY it to all your given terms in other words!)</h3><h3 /><h3>
</h3><h3 /><h3>Good luck on your assignment and enjoy your day!</h3><h3 /><h3>~
</h3>
<h2>3/9</h2>
If you multiply the numerator and the denominator by the same number, it will be equal to 1/3.
For example:
1/3 * 3/3 = 3/9
1/3 * 8/8 = 8/24
