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3 years ago

Hey people! I sorta need help. :))

Physics

2 answers:

il63 [147K]3 years ago

4 0

Answer:

1. Attract

2. Repel

3. Attract

4 Repel

always remember when dealing with magnets, Opposites attract

Gwar [14]3 years ago

4 0

ATTRACT
REPEL
ATTRACT
REPEL

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A bullet is fired straight up from a gun with a

melamori03 [73]

Answer: 815.51 m

Explanation:

This situation is related to projectile motion or parabolic motion, in which the initial velocity of the bullet has only y-component, since it was fired straight up. In addition, we are dealing with constant acceleration (due gravity), therefore the following equations will be useful to solve this problem:

$V=V_{o}+gt$ (1)

$V^{2}=V_{o}^{2}+2gy$ (2)

Where:

$V$ is the final velocity of the bullet

$V_{o}=152 m/s$ is the initial velocity of the bullet

$g=-9.8 m/s^{2}$ is the acceleration due gravity, always directed downwards

$t=6.9 s$ is the time

$y$ is the vertical position of the bullet at $t=6.9 s$

Let's begin by finding $V$ from (1):

$V=152 m/s-9.8 m/s^{2}(6.9 s)$ (3)

$V=84.38 m/s$ (4)

Now we have to substitute (4) in (2):

$(84.38 m/s)^{2}=(152 m/s)^{2}-2(9.8 m/s^{2})y$ (5)

Isolating $y$ :

$y=815.511 m$ This is the displacement of the bullet after 6.9 s

8 0

3 years ago

There are four charges, each with a magnitude of 2.06 µC. Two are positive and two are negative. The charges are fixed to the co

mars1129 [50]

Answer:

0.208 N

Explanation:

We are given that

$q_1=q_2=2.06\mu C=2.06\times 10^{-6} C$

$q_3=q_4=-2.06\mu C=-2.06\times 10^{-6} C$

Distance,d=0.41 m

The magnitude of the net electrostatic force experienced by any charge at point 4

Net force, $F_{net}=\sqrt{F^2_1+F^2_3+2F_1F_3cos90^{\circ}}-F_2$

$F_1=F_3=F$

$F_{net}=\sqrt{F^2+F^2+0}-F_2$

$F_{net}=\sqrt 2F-F_2$

$F=\frac{kq^2}{d^2}$

$F_2=\frac{Kq^2}{2d^2}$

$F_{net}=\frac{\sqrt 2kq^2}{d^2}-\frac{kq^2}{2d^2}=\frac{kq^2}{d^2}(\sqrt 2-\frac{1}{2})$

Where $k=9\times 10^9$

$F_{net}=\frac{9\times 10^9\times (2.06\times 10^{-6})^2}{(0.41)^2}(\sqrt 2-\frac{1}{2})$

$F_{net}=0.208 N$

3 0

3 years ago

In figure 16-2 is the temperature of the material within the cylinder greatest during the intake stroke, compression stroke, pow

erastovalidia [21]

Technically, we have no way of knowing that without seeing Figure 16-2.
So the question should be reported for incomplete content. But I'm
going to take a wild stab at it anyway.

There's so much discussion of 'cylinder' and 'strokes' in the question,
I have a hunch that it's talking about the guts of a 4-stroke internal
combustion gasoline engine.

If I'm right, then the temperature of the material within the cylinder is
greatest right after the spark ignites it. At that instant, the material burns,
explodes, expands violently, and drives the piston down with its stiff shot
of pressure.

This is obviously happening because of the great, sudden increase in
temperature when the material ignites and explodes.

It hits the piston with pressure, which leads directly to the power stroke.

5 0

3 years ago

What is 25 degrees Celsius equal to in Fahrenheit? I need to know how to do it to, so give me a formula, and it would help if yo

andreev551 [17]

C= 5/9*(F - 32) so F=C*9/5 + 32

F= 25*9/5 +32 = 77 Fahrenheit

5 0

3 years ago

Gibbons move through the trees by swinging from successive handholds, as we have seen. To increase their speed, gibbons may brin

Sedbober [7]

By bring their legs close to their bodies, they are decreasing the length of the pendulum which help them move more quickly.

A pendulum is nothing but a body suspended from a fixed point so that it can swing back and forth under the influence of gravity.

Here in this case Gibbons are bringing their legs close to their bodies and reducing the length of the pendulum. Since as the length of the pendulum increases the speed of the movement will be reduced. By bringing their legs close to their bodies they are reducing the length and in turn their speed increase and they move quickly.

To learn more about pendulum, visit here

brainly.com/question/14759840

#SPJ4

5 0

2 years ago