A boy pushes a 50 kilogram wagon with a force of 4 N east while an orangutan pushes the wagon

Which of the following is another way to say that, in energy transforms, some energy is always converted unusable or unwanted fo

ikadub [295]

Option B. By not being 100% efficient, it shows that some energy is lost to unusable or unwanted sources

4 0

3 years ago

The blank is the the distance between two crests or two troughs on a transverse wave. It is also the distance between compressio

den301095 [7]

"Wavelength" is the distance between two crests or two Troughs.

It is the <span>distance between compressions or the distance between rarefactions on a longitudinal wave too!

So, your final answer is "Wavelength".

Hope this helps!!</span>

6 0

3 years ago

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IWhat is a hypothesis?

Setler79 [48]

Answer:

a hypothesis is a explanation made on the basis of limited evidence

Explanation:

4 0

3 years ago

Read 2 more answers

10. A tennis ball rolled off the edge of a table that has a height of 1,00 m.

Maslowich

Answer:

The answer is " $1.6\ \frac{m}{s}$ "

Explanation:

Distance= 0.72 meter

time= 0.45 second

The formula for horizontal velocity:

$horizontal \ velocity = \frac{distance}{time}\\\\$

$=\frac{0.72}{ 0.45}\\\\= 1.6 \ \frac{m}{s}\\\\$

5 0

3 years ago

A physicist drives through a stop light. When he is pulled over, he tells the police officer that the Doppler shift made the red

Colt1911 [192]

Answer:

$6.59\times 10^7m/s$

Explanation:

We are given that

Wavelength of red light= $\lambda=635nm$

Wavelength of green light= $\lambda'=510 nm$

We have to find the speed of physicist traveling according to his own testimony.

We know that

$\frac{\lambda}{\lambda'}=\sqrt{\frac{1+\frac{v}{c}}{1-\frac{v}{c}}}$

Where $c=3\times 10^8m/s$

Substitute the values

$\frac{635}{510}=\sqrt{\frac{1+\frac{v}{c}}{1-\frac{v}{c}}}$

$1.25=\sqrt{\frac{1+\frac{v}{c}}{1-\frac{v}{c}}}$

Squaring on both sides

$1.5625=\frac{1+\frac{v}{c}}{1-\frac{v}{c}}$

$1.5625-1.5625\frac{v}{c}=1+\frac{v}{c}$

$1.5625-1=\frac{v}{c}+1.5625\frac{v}{c}=\frac{v}{c}(1+1.5625)$

$0.5625=2.5625\frac{v}{c}$

$v=\frac{0.5625c}{2.5625}=\frac{0.5625\times 3\times 10^8}{2.5625}$

$v=6.59\times 10^7m/s$

8 0

3 years ago