The answer is (3) sodium nitrate. Sodium nitrate is NaNO3. The bond between N and O ion is covalent bond and the bond between Na+ and NO3- is ionic bond.
<span>Answer is </span>(3)
- Sodium Nitrate.<span>
</span>Normally ionic bonds can be seen between
metals and non-metals while covalent
bonds presentbetween
non-metals. Another thing that determines the bond nature is electronegativity
value of the atoms.
If the electronegativitydifference
is high, then that bond tends to be an ionic bond.<span> </span><span>Sodium nitrate consists of </span>Na⁺<span> and </span>NO₃⁻ ions. Hence, the bond
between Na⁺ and NO₃⁻<span> is an </span>ionic
bond. <span><span>
NO</span>₃⁻ </span><span>is made from </span>N <span>and </span>O<span>. Both are </span>non-metallic
atoms. <span>The </span>electronegativities <span>of </span>N <span>and </span>O <span>are </span>3.0 <span>and </span>3.5 <span>respectively. Hence, there is </span>no
big difference between
electronegativity values (3.5 - 3.0 = 0.5<span>). Hence, the bond
between N and O is a </span><span>covalent
bond. </span>
<span>2H2O= 2H2 + O2 </span> We are given the amount of oxygen to be produced in the reaction. The starting point for the calculations will be this amount.
50 g ( 1 mol O2 / 32 g O2 ) ( 2 mol H2O / 1 mol O2 ) ( 18.01 g H2O / 1 mol H2O) = 56.28 g of H2O is needed.
