All categories

3 years ago

Which of these 2A elements has the largest atomic radius?

Chemistry

1 answer:

olya-2409 [2.1K]3 years ago

5 0

Answer: Option (E) is the correct answer.

Explanation:

When we move from top to bottom in a group then there occurs an increase in atomic size of the atoms due to increase in the number of electrons.

For example, in group 2A elements beryllium is the smallest in size whereas radium being at the bottom is the largest in size.

Also, atomic number of beryllium is 4 and atomic number of radium is 88.

Thus, we can conclude that out of the given options radium is the 2A element which has the largest atomic radius.

You might be interested in

What is volume if the diameter of a sphere is 14cm

lisov135 [29]

Volume = (4/3) × π × r^3
R = 1/2 D
R = 7

V = 4/3 x π x 7^3

Exact Form:
1372 π/ 3

Decimal Form:
1436.75504024

6 0

3 years ago

What most likely happens during this reaction

Bad White [126]

Answer:

I think that it is A I am sorry if I am wrong

Explanation:

8 0

2 years ago

Question 25 pts

777dan777 [17]

The answer is a, because the population number has increased.

4 0

2 years ago

Read 2 more answers

What would the volume of gas be at 150 c if it had a volume of 693 ml at 45 c

marissa [1.9K]

Answer:

$\boxed{\text{922 mL}}$

Explanation:

The pressure is constant, so we can use Charles' Law to calculate the volume.

$\dfrac{V_{1}}{T_{1}} = \dfrac{V_{2}}{T_{2}}$

Data:

V₁ = 693 mL; T₁ = 45 °C

V₂ = ?; T₂ = 150 °C

Calculations:

(a) Convert temperature to kelvins

T₁ = ( 45 + 273.15) = 318.15 K

T₂ = (150 + 273.15) = 423.15 K

(b) Calculate the volume

$\dfrac{ 693}{318.15} = \dfrac{ V_{2}}{423.15}\\\\2.178 = \dfrac{ V_{2}}{423.15}\\\\V_{2} = 2.178 \times 423.15 = \boxed{\textbf{922 mL}}$

5 0

3 years ago

Un estudiante debe preparar una disolución 2M de NaCl (58,44 g/mol) en un recipiente de 7L. ?Cuántos gramos de NaCl debe agregar

Gnesinka [82]

Answer:

818.2 g.

Explanation:

Molarity is the no. of moles of solute per 1.0 L of the solution.

M = (no. of moles of NaCl)/(Volume of the solution (L))

M = 2.0 M.

no. of moles of NaCl = ??? mol,

Volume of the solution = 7.0 L.

∴ (2.0 M) = (no. of moles of NaCl)/(7.0 L)

∴ (no. of moles of NaCl) = (2.0 M)*(7.0 L) = 14.0 mol.

To find the mass of NaCl, we can use the relation:

no. of moles of NaCl = mass/molar mass

∴ mass of NaCl = (no. of moles of NaCl)*(molar mass) = (14.0 mol)*(58.44 g/mol) = 818.2 g.

3 0

3 years ago