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LenKa [72]
2 years ago
13

In a laboratory experiment, John uses a mesh to separate soil particles from water. Which technique of separation is he using?

Chemistry
1 answer:
nekit [7.7K]2 years ago
7 0
Pretty much, if I were going to separate small solid particles, I could use like a piece of paper. I used some type of piece of paper when I was trying to separate some particles during science.
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Which is more polar: carbon disulfide or sulfur difluoride
Ilya [14]
<span>Carbon disulfide. hope that helped</span>
4 0
3 years ago
Given the balanced chemical equation, SiO2(s) + 4 HF(g) → SiF4(g) + 2 H2O(l) ΔH°rxn = −184 kJ Determine the mass (in grams) of H
Ostrovityanka [42]

Answer:

mass HF = 150.05 g

Explanation:

  • SiO2(s) + 4HF(g) → SiF4(g) + 2H2O(l)

⇒ Q = (ΔH°rxn * mHF) / (mol HF * MwHF )

∴ MwHF = 20.0063 g/mol

∴ mol HF = 4 mol

∴ ΔH°rxn = - 184 KJ

∴ Q = 345 KJ

mass HF ( mHF ):

⇒ mHF = ( Q * mol HF * MwHF ) / ΔH°rxn

⇒ mHF = ( 345 KJ * 4mol HF * 20.0063 g/mol ) / 184 KJ

⇒ mHF = 150.05 g HF

3 0
3 years ago
Calculate the molar solubility of silver chloride in 0.15 M sodium chloride.
Alex777 [14]

Answer:

S = 1.1 × 10⁻⁹ M

Explanation:

NaCl is a strong electrolyte that dissociates according to the following expression.

NaCl(aq) → Na⁺(aq) + Cl⁻(aq)

Given the concentration of NaCl is 0.15 M, the concentration of Cl⁻ will be 0.15 M.

We can find the molar solubility (S) of AgCl using an ICE chart.

      AgCl(s) ⇄ Ag⁺(aq) + Cl⁻(aq)

I                         0            0.15

C                      +S              +S

E                        S            0.15+S

The solubility product (Ksp) is:

Ksp = 1.6 × 10⁻¹⁰ = [Ag⁺].[Cl⁻] = S (0.15 + S)

If we solve the quadratic equation, the positive result is S = 1.1 × 10⁻⁹ M

6 0
2 years ago
Read 2 more answers
How many grams of KCN are in 10.0 ml of a 0.10 M solution?
attashe74 [19]

Explanation:

As it is known that molarity is the number of moles present in a liter of solution.

Mathematically,       Molarity = \frac{no. of moles}{Volume in liter}

As it is given that molarity is 0.10 M and volume is 10.0 ml. As 1 ml equals 0.001 L. Therefore, 10.0 ml will also be equal to 0.01 L.

Hence, putting these values into the above formula as follows.

                  Molarity = \frac{no. of moles}{Volume in liter}

                  0.10 M = \frac{no. of moles}{0.01 L}

                        no. of moles = 0.001 mol

As molar mass of KCN is equal to 65.12 g/mol. Therefore, calculate the mass of KCN as follows.

                 No. of moles = \frac{mass}{molar mass}

                                 0.001 mol = \frac{mass}{65.12 g/mol}

                                 mass = 0.06152 g

Thus, we can conclude that 0.06152 grams of KCN are in 10.0 ml of a 0.10 M solution.

3 0
3 years ago
What is the guiding formula for combustion reactions​
IgorLugansk [536]

Answer:

Explanation: so a combustion occurs when we react a substance with oxygen .you commonly call this "burning'' .therefore combustion will always include oxygen in the equation and the product will include carbon dioxide and give off water vapours

Therefore the general equation for a complete combustion reaction would be

Fuel + O2 ------ CO2 + H2O

8 0
3 years ago
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