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kipiarov [429]
3 years ago
11

You are given three radioactive samples (α, β, and γ) and can only dispose of one. The other two you must keep, one in your hand

, the other in your pocket. How would you minimize your exposure risk?
Physics
1 answer:
Dennis_Churaev [7]3 years ago
8 0

Answer:

Keep alpha in hand, keep beta in pocket, dispose of gamma radioactive sample

Explanation:

<u>Alpha particles: </u>

Alpha particles are the particles which cannot penetrate most of the matter. The outer layer of the skin or a piece of paper may be sufficient to stop the alpha particles.

The Radioactive material that emits the alpha particles  can be harmful when they are swallowed, inhaled, or absorbed into blood stream through wounds.

<u>Thus, α radioactive sample can be kept in hand.</u>

<u>Beta particles: </u>

Beta particles are the particles which can be stopped by a few mm of a substance like aluminum layer or by clothing.

Beta particles can penetrate the skin and can cause radiation damage, such as skin burns.

<u>Thus, β radioactive sample can be kept in pocket.</u>

<u>Gamma rays: </u>

Gamma rays are the rays which are penetrating. Many feet of concreted layers or some inches of metal lead are needed to stop them.

Gamma rays are the radiation hazard for the entire human body.

They attack the DNA and can cause lethal defects.

<u>Thus, γ radioactive sample is to be disposed off.</u>

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Answer:

2 x 10^-8

Explanation:

the formula of wavelength is

the speed divided by frequency

so you have the speed given = 3.0x10^8m/s

and frequency = 1.5×10^16 Hz

so wavelength = 3.0x10^8m/s / 1.5x10^16 Hz

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2. What is the mass of an object that has 50000 J
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Answer:

m= 666.67 or 667

Explanation:

KE= 50000 J

v= 75 m/s

m= ?

M= 50000 / 75

m= 666.67  or 667

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What are groups 1,2 and 3 examples of on the periodic table
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Read 2 more answers
Water ice has a density of 0.91 g/cm2, so it will float in liquid water. Imagine you have a cube of ice, 10 cm on a side. a. Wha
Reptile [31]

Answer:

(i) W = 8.918 N

(ii) V = 9.1 \times 10^{-4} m^3

(iii) d = 9.1 cm

Explanation:

Part a)

As we know that weight of cube is given as

W = mg

W = \rho V g

here we know that

\rho = 0.91 g/cm^3

Volume = L^3

Volume = 10^3 = 1000 cm^3

now the mass of the ice cube is given as

m = 0.91 \times 1000 = 910 g

now weight is given as

W = 0.910 \times 9.8 = 8.918 N

Part b)

Weight of the liquid displaced must be equal to weight of the ice cube

Because as we know that force of buoyancy = weight of the of the liquid displaced

W_{displaced} = 8.918 N

So here volume displaced is given as

\rho_{water}Vg = 8.918

1000(V)9.8 = 8.918

V = 9.1 \times 10^{-4} m^3

Part c)

Let the cube is submerged by distance "d" inside water

So here displaced water weight is given as

W = \rho_{water} (L^2 d) g

8.918 = 1000(0.10^2 \times d) 9.8

d = 0.091 m

so it is submerged by d = 9.1 cm inside water

4 0
3 years ago
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