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3 years ago

In order to make a ramp that is 3ft high and covers4ft of ground how long must the ramp be

1 answer:

6 0

This seems like a right angle triangle situation
the height is 3ft
the base is 4ft
so we're looking for the hypothenus
so we can use the Pythagoras Theorem
which is
the square of the hypothenus is equal to the sum of the square of the two other sides
hyp^2 is equal to opp^2+ adj^2
hyp^2 equals to 3^2 + 4^2
9+16
25
hyp^2 equals to 25
$\sqrt{25}$
equals to 5
the ramp has to be 5ft long

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A plant is thrown straight

olchik [2.2K]

The time taken for the plant to hit the ground from a distance of 7.01m and at a velocity of 8.84m/s is 1.59s.

<h3>How to calculate time?</h3>

The time taken for a motion to occur can be calculated using the following formula:

v² = u² - 2as

Where;

v = final velocity
u = initial velocity
s = distance
a = acceleration

8.84² = 0² + 2 × a × 7.01

78.15 = 14.02a

a = 5.57m/s²

V = u + at

8.84 = 0 + 5.57t

t = 1.59s

Therefore, the time taken for the plant to hit the ground from a distance of 7.01m and at a velocity of 8.84m/s is 1.59s.

Learn more about time at: brainly.com/question/13170991

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2 years ago

A stone is thrown straight up from the edge of a roof, 925 feet above the ground, at a speed of 20 feet per second. Remembering

Black_prince [1.1K]

<h2>Answer: 469 feet</h2>

Explanation:

This problem is a good example of Vertical motion, where the main equation for this situation is:

$y=y_{o}+V_{o}t-\frac{1}{2}gt^{2}$ (1)

Where:

$y$ is the height of the stone at 6s (the value we want to find)

$y_{o}=925ft$ is the initial height of the stone

$V_{o}=20ft/s$ is the initial velocity of the stone

$t=6s$ is the time at which we need to find the height

$g=32ft/s^{2}$ is the acceleration due to gravity

Having this clear, let's find $y$ from (1):

$y=925ft+(20ft/s)(6s)-\frac{1}{2}(32ft/s^{2})(6s)^{2}$ (2)

Finally:

$y=469ft$ This is the height of the stone at t=6s

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3 years ago

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3 years ago

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The answer is <span>A.)the greenhouse effect
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3 years ago

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Vladimir79 [104]

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