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Elodia [21]
3 years ago
7

A boat travels at 15 m/s in a direction 45° east of north for an hour. The boat then turns and travels at 18 m/s in a direction

5° north of east for an hour. What is the magnitude of the boat’s resultant velocity? Round your answer to the nearest whole number. m/s What is the direction of the boat’s resultant velocity? Round your answer to the nearest whole degree. ° north of east

Physics
2 answers:
taurus [48]3 years ago
8 0

Answer:

31m/s

23.17°

Explanation:

Given the following :

From the diagram attached :

AB = 15m/s, BC = 18m/s, AC = a = resultant

Resolving Velocity into both vertical and horizontal component.

Kindly see attached picture for detailed explanation.

Ilya [14]3 years ago
3 0

The first blank is 31m/s

The second blank is 23°

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Answer:

flexible covering

Explanation:

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Which of the following temperatures is the coldest? A) 5 degrees B)0 degrees C) -15 degrees D) -7 degrees
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It’s c -15 degrees because it it has below O which is below freezing
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When she rides her bike, she gets to her first classroom building 36 minutes faster than when she walks. Of her average walking
postnew [5]

Answer:

d=2.4\ miles

Explanation:

Given:

  • average walking speed, v_w=3\ mph
  • average biking speed, v_b=12\ mph

<u>According to given condition:</u>

t_w=t_b+\frac{36}{60}

where:

t_w= time taken to reach the building by walking

t_b= time taken to reach the building by biking

We know that,

\rm time=\frac{distance}{speed}

so,

\frac{d}{v_w} =\frac{d}{v_b} +\frac{36}{60}

\frac{d}{3}=\frac{d}{12} +\frac{3}{5}

d=2.4\ miles

7 0
3 years ago
Read 2 more answers
A ball is launched from ground level at 20 m/s at an angle of 40° above the
DedPeter [7]

(a) The ball's height <em>y</em> at time <em>t</em> is given by

<em>y</em> = (20 m/s) sin(40º) <em>t</em> - 1/2 <em>g t</em> ²

where <em>g</em> = 9.80 m/s² is the magnitude of the acceleration due to gravity. Solve <em>y</em> = 0 for <em>t</em> :

0 = (20 m/s) sin(40º) <em>t</em> - 1/2 <em>g t</em> ²

0 = <em>t</em> ((20 m/s) sin(40º) - 1/2 <em>g t</em> )

<em>t</em> = 0   or   (20 m/s) sin(40º) - 1/2 <em>g t</em> = 0

The first time refers to where the ball is initially launched, so we omit that solution.

(20 m/s) sin(40º) = 1/2 <em>g t</em>

<em>t</em> = (40 m/s) sin(40º) / <em>g</em>

<em>t</em> ≈ 2.6 s

(b) At its maximum height, the ball has zero vertical velocity. In the vertical direction, the ball is in free fall and only subject to the downward acceleration <em>g</em>. So

0² - ((20 m/s) sin(40º))² = 2 (-<em>g</em>) <em>y</em>

where <em>y</em> in this equation refers to the maximum height of the ball. Solve for <em>y</em> :

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8 0
2 years ago
two forces whose magnitude are in ratio of 3:5 gives a resultant of 35N.if the angle of inclination is 60degree.calculate the ma
nadya68 [22]

Answer:

the magnitude of first force = 3 × 5= 15 N

ANd, the magnitude of second force = 5 × 5 = 25 N

Explanation:

The computation of the magnitude of the each force is shown below:

Provided that

Ratio of forces = 3: 5

Let us assume the common factor is x

Now

first force =  3x

And, the second force = 5x

Resultant force = 35 N

The Angle between the forces = 60 degrees  

Based on the above information

Resultant force i.e. F = √ F_1^2 +F_2^2 + 2 F_1F_2cos\theta

35 = √[(3x)²+ (5x)²+ 2 (3x)(5x) cos 60°]

 35 =√ 9x² + 25x² + 15x²    (cos 60° = 0.5)

35 = √49 x²

 x = 5

So, the magnitude of first force = 3 × 5= 15 N

ANd, the magnitude of second force = 5 × 5 = 25 N

7 0
3 years ago
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