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3 years ago

The first law of thermodynamics states that . Is this also a statement of the principle of conservation of energy?

Physics

2 answers:

Gekata [30.6K]3 years ago

7 0

B. Should be your answer.

nikdorinn [45]3 years ago

5 0

The correct choice is

Yes, the heat that flows into the system is used to change the internal energy of the gas and becomes work done by the piston.

According to first law of thermodynamics,

Q = W + U

where Q = heat flowing into the system

W = work done by the system

U = change in internal energy of the system

hence the total energy remains same all the time which is what the principle of conservation of energy states.

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Hurricane or typhoons occur when large areas of the open ocean soak up heat from the sun t or f

11Alexandr11 [23.1K]

Answer: true

Explanation:

3 0

2 years ago

An object with mass 3.5 kg is attached to a spring with spring stiffness constant k = 270 N/m and is executing simple harmonic m

Elanso [62]

Answer:

Part a)

A = 0.066 m

Part b)

maximum speed = 0.58 m/s

Explanation:

As we know that angular frequency of spring block system is given as

$\omega = \sqrt{\frac{k}{m}}$

here we know

m = 3.5 kg

k = 270 N/m

now we have

$\omega = \sqrt{\frac{270}{3.5}}$

$\omega = 8.78 rad/s$

Part a)

Speed of SHM at distance x = 0.020 m from its equilibrium position is given as

$v = \omega \sqrt{A^2 - x^2}$

$0.55 = 8.78 \sqrt{A^2 - 0.020^2}$

$A = 0.066 m$

Part b)

Maximum speed of SHM at its mean position is given as

$v_{max} = A\omega$

$v_{max} = 0.066(8.78) = 0.58 m/s$

4 0

2 years ago

What is the change in internal energy if 60J of heat are released from a system and 20J of work is done on the system? Use U=Q-W

Ganezh [65]

D because 60-20= 40J

5 0

2 years ago

How can I feel pain when I hit a table with my bare hands (Physics)

Sidana [21]

When your hand hits the table the table will vibrate and your hand will be numb for two to three seconds

6 0

3 years ago

A heavy-duty shock absorber is compressed 4 cm from its equilibrium position by a mass of 700nbspkg. How much work is required

tia_tia [17]

Answer:

Explanation:

A mass of 700 kg will exert a force of

700 x 9.8

= 6860 N.

Amount of compression x = 4 cm

= 4 x 10⁻² m

Force constant K = force of compression / compression

= 6860 / 4 x 10⁻²

= 1715 x 10² Nm⁻¹.

Let us take compression of r at any moment

Restoring force by spring

= k r

Force required to compress = kr

Let it is compressed by small length dr during which force will remain constant.

Work done

dW = Force x displacement

= -kr -dr

= kr dr

Work done to compress by length d

for it r ranges from 0 to -d

Integrating on both sides

W = $\int\limits^{-4}_0 {kr} \, dr$

= [ kr²/2]₀^-4

= 1/2 kX16X10⁻⁴

= .5 x 1715 x 10² x 16 x 10⁻⁴

= 137.20 J

3 0

2 years ago