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3 years ago

The conversion factor 100mL/1 L would be used to change what

Chemistry

1 answer:

ValentinkaMS [17]3 years ago

8 0

Answer:

Liters to milliliters.

Explanation:

Conversion factors are used to convert from one unit to another. The unit you are converting from goes in the denominator, and the unit you are converting to goes in the numerator. Since liters is in the denominator, you are converting from liters to another unit. Since milliliters is in the numerator, you are converting to that unit. Therefore, you would be converting from liters to milliliters.

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Answer:

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3 years ago

If sulfur dioxide and oxygen can be made into sulfur trioxide, what is the reverse reaction? A. SO3 +O2à SO3 B. 2SO2 + O2à 2SO3

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3 years ago

Read 2 more answers

Determine the empirical formula. a 3.880g sample contains 0.691g of magnesium , 1.84 g of sulfur , and 1.365 g of oxygen .

Aliun [14]

Answer:

Mg S2 O3

Explanation:

.691 g of Mg is .284 mole

1.84 g of S is .5739 mole

1.365 g of O is .8531 mole you can see the ratio is ~ 1 :2 :3

Mg S2 O3

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2 years ago

Non-living factors in an ecosystem are ______.

mash [69]

Answer:

B. abiotic

Explanation:

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2 years ago

A chemical reaction produces 3.81g potassium chloride (KCl). How many formula units of potassium chloride are there? *Find Molar

Aleks04 [339]

Answer:

The number of formula units in 3.81 g of potassium chloride (KCl) is approximately 3.08 × 10²²

Explanation:

The given parameters is as follows;

The mass of potassium chloride produced in the chemical reaction (KCl) = 3.81 g

The required information = The number of formula units of potassium chloride (KCl)

The Molar Mass of KCl = 74.5513 g/mol

$The \ number \ of \ moles \ of \ a \ substance, n = \dfrac{The \ mass \ of \ the substance}{The \ Molar \ Mass \ of \ the \ substance}$

Therefore, we have;

$The \ number \ of \ moles \ of \ KCl= \dfrac{3.81 \ g}{74.5513 \ g/mol} \approx 0.051106 \ moles$

1 mole of a substance, contains Avogadro's number (6.022 × 10²³) of formula units

Therefore;

0.051106 moles of KCl contains 0.051106 × 6.022 × 10²³ ≈ 3.077588 × 10²² formula units

From which we have, the number of formula units in 3.81 g of potassium chloride (KCl) ≈ 3.08 × 10²² formula units.

8 0

3 years ago