Answer:
0.6425 moles of 
is required to react with 25.7 grams of 
.
Explanation:
mas of oxygen gas = 25.7 g
moles of oxygengas = 
According to reaction given above, 5 moles of oxygen gas reacts with 4 moles of ammonia gas.
Then 0.8031 moles of oxygen gas will react with :
of ammonia gas
0.6425 moles of is required to react with 25.7 grams of .
Answer:
The answer to your question is 4 M
Explanation:
Data
NaCl 2 moles
Volume = 0.5 l
Molarity = M
Process
1.- Write the formula of Molarity
2.- Substitution
3.- Simplification and result
Molarity = 4 M
The curved movement of air or water is the result of which of these:
The answer is B
Explanation:
Experiment because water boils at 100°c and ethanol 80°co
1) Convert 12.9 liters of Oxygen to mol at the given conditions:
PV = nRT ⇒ n = PV/RT
n = [1.2atm*12.9 l] / [0.082 atm l /K mol * 297K]
n = 0.636 mol of O2
2) use the stoichiometry derived from the balanced chemical equation
1mol C2H4 / 3 mol O2 = x mol C2H4 / 0.636 mol O2
x = 0.636 / 3 mol O2 = 0.212 mol O2.
Answer: 0.212 mol O2
