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Sveta_85 [38]
3 years ago
5

A gas turbine receives a mixture having the following molar analysis: 10% CO2, 19% H2O, 71% N2 at 720 K, 0.35 MPa and a volumetr

ic flow rate of 3.2 m3 /s. The mixture exits the turbine at 380 K, 0.11 MPa. For adiabatic operation with negligible kinetic and potential energy effects, determine the power developed at steady state, in kW.
Engineering
1 answer:
Sliva [168]3 years ago
4 0

Answer:

2074.2 KW

Explanation:

<u>Determine power developed at steady state </u>

First step : Determine mass flow rate  ( m )

m / Mmax = ( AV )₁ P₁ / RT₁   -------------------- ( 1 )

<em> where : ( AV )₁ = 8.2 kg/s,  P₁ = 0.35 * 10^6 N/m^2,   R = 8.314 N.M / kmol , </em>

<em>  T₁  = 720 K . </em>

insert values into equation 1

m  = 0.1871  kmol/s  ( mix )

Next : calculate power developed at steady state ( using ideal gas tables to get the h values of the gases )

W( power developed at steady state )

W = m [ Yco2 ( h1 - h2 )co2

Attached below is the remaining  part of the detailed solution

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Answer:

Technician b is correct

Explanation:

Before adjusting drive-belt tension, it is very important to check the vehicle workshop manual for specified belt tension, so that you can match your reading against the specification in the vehicle's service manual. If the tension reading you have matches the suggested reading in the vehicle's service manual and the belt is not damaged then you do not need to proceed any further. But if the reading does not match, then you can adjust the belt tension.

Therefore, technician b is correct.

5 0
3 years ago
How engineer can find problems and solutions <br><br><br> Give example
Mademuasel [1]

Answer:

They find problems and solutions by working together

Explanation:

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Which of the following applies to a module?
Ipatiy [6.2K]

Answer:

D all of the above

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because I said so

3 0
2 years ago
Instead of running blood through a single straight vessel for a distance of 2 mm, one mammalian species uses an array of 100 tin
Marina CMI [18]

Solution:

Given that :

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Therefore, the equation of a single straight vessel is given by

$F_{f_1}=\frac{8flQ_1^2}{\pi^2gd_1^5}$    ......................(i)

So there are 100 similar parallel pipes of the same cross section. Therefore, the equation for the area is

$\frac{\pi d_1^2}{4}=1000 \times\frac{\pi d_2^2}{4} $

or $d_1=10 \ d_2$

Now for parallel pipes

$H_{f_2}= (H_{f_2})_1= (H_{f_2})_2= .... = = (H_{f_2})_{10}=\frac{8flQ_2^2}{\pi^2 gd_2^5}$  ...........(ii)

Solving the equations (i) and (ii),

$\frac{H_{f_1}}{H_{f_2}}=\frac{\frac{8flQ_1^2}{\pi^2 gd_1^5}}{\frac{8flQ_2^2}{\pi^2 gd_2^5}}$

       $=\frac{Q_1^2}{Q_2^2}\times \frac{d_2^5}{d_1^5}$

       $=\frac{(1000)^2}{(10)^2}\times \frac{d_2^5}{(10d_2)^5}$

       $=\frac{10^6}{10^7}$

Therefore,

$\frac{H_{f_1}}{H_{f_2}}=\frac{1}{10}$

or $H_{f_2}=10 \ H_{f_1}$

Thus the answer is option A). 10

7 0
3 years ago
How would you describe the stability of the atmosphere if you noted a dry adiabatic rate of 10ºC/1000 meters, a wet adiabatic ra
muminat

Answer:

conditional instability (Γd >  Γe > Γw)

Explanation:

Given;

dry adiabatic rate, Γd = 10ºC/1000 meters

wet adiabatic rate, Γw= 6.5ºC/1000 meters

environmental lapse rate, Γe = 7.8ºC/1000 meters

Stability of the atmosphere can be described as Absolute stability, Absolute instability or conditional instability.

Conditions for Absolute stability:

Γd > Γw > Γe

Conditions for Absolute instability:

Γe > Γd > Γw

Conditions for conditional instability:

Γd >  Γe > Γw

Thus, conditional instability satisfies the given values of the atmospheric condition: Γd (10) > Γe (7.8) >  Γw (6.5)

3 0
3 years ago
Read 2 more answers
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