Answer:
45.873 KN/mL is the ultimate bearing capacity of the foundation.
Explanation:
C' = 10.0 kN/m², Ф' = 25, r = 18 kN/m²
ration of Df/B ≤ 1 , Df ≤ B (1 ≤ 2.5m)
It is a shallow foundation
∴ Ultimate bearing Capacity
qu = C' + r
.
+
Br
NФ = tan²(45 + Ф/2)
= tan²(45 - 25/2)
= 0.41
Nq = NФ×e^(πtanФ') = 0.41e^(πtan25)
= 1.756
Nr = 1.8tanФ(Nq - 1) = 1.8tan25(1.756 - 1)
= 0.634
Nc = 1.621
putting the above values in equation.
qu = 45.873 KN/mL
Answer:
Explanation:
Energy : Energy can be defined as both qualitative and quantitative property that can be given to an object in the form of work or heat.
For example - water stored in a tank at a height,h from the ground has a potential energy of U = ρgh.
Mathematically, Energy of water stored in a tank is
U = ρ.g.h
where, ρ is water density
g is acceleration due to gravity
h is height of water tank from ground
Power : Power is defined as rate at which work can be done.
For example - When a force F is applied to an object to move it through a distance d in time t seconds is an example of power delivered.
Mathematically, Power = Work done / Time
Work : When a force act on a body and the body moves, work is said to be done.
For example - Gas confined in a cylinder by a piston. The gas expands when it is heated, doing work on the piston.
Mathematically, Work,W = F X d
where, F is force
d is distance
Heat : Heat is a form of energy which is produced as a result of motion of atoms and particles.
For example - while increasing the temperature of water, heat is added to the water by means of gas burner or any other form.
Mathematically we can calculate heat release or heat absorb by
q = m.C.ΔT
where q is heat
m is mass
C is specific heat capacity
ΔT is change in temperature
Answer:
speed = 16.44 m/s
Acceleration = 71.36 m/s²
Explanation:
Given data
Speed ( N) = 240 rpm
angle = 45°
stoke length(L) = 750 mm
length of rod ( l ) = 1500 mm
To find out
the piston speed and acceleration
Solution
we find speed by this formula
speed = r ω (sin(θ) + (sin2(θ)/ 2n)) ...................1
here we have find r and ω
ω = 2 N / 60
so ω = 2 × 240 / 60
ω = 25.132 rad/s
n = l/r = 1500/750 = 2
we know L = 2r
so r = L/2 = 750/2 = 375 mm
put these value in equation 1
speed = 375 × 25.132 (sin(45) + (sin2(45)/ 2×2))
speed = 16444.811823 mm/s = 16.44 m/s
Acceleration = r ω² (cos(θ) + (cos2(θ)/ n)) ...................2
put the value r, ω and n in equation 2
Acceleration = r ω² (cos(θ) + (cos2(θ)/ n))
Acceleration = 375 × (25.132)² (cos(45) + (cos2(45)/2))
Acceleration = 71361.363659 = 71.36 m/sec²