Answer:
resolved shear stress = 22.0 MPa
so we can say that here single crystal will yield because critical resolved shear stress i.e 20.7 MPa is less than resolved shear stress i.e 22.0 MPa
Explanation:
given data
angles φ = 43.1 degrees
angles λ = 47.9 degrees
shear stress = 20.7 MPa (3000 psi)
stress σ = 45 MPa (6500 psi)
solution
we have given shear stress so first we calculate here resolved shear stress that is express as
resolved shear stress = σ cosφ cosλ .................1
here σ is stress and φ and λ are angles given
so put here value we get
resolved shear stress = σ cosφ cosλ
resolved shear stress = 45 cos(43.1) cos(47.9)
resolved shear stress = 22.0 MPa
so we can say that here single crystal will yield because critical resolved shear stress i.e 20.7 MPa is less than resolved shear stress i.e 22.0 MPa
Answer:
1.14 * 10^-3 amperes
Explanation:
According to ohms law
V = IR ---- ( 1 )
V = voltage = 2.4 * 10^3 v
I = current = ?
R = resistance = 2.1 * 10^6 Ω
from equation 1
I = V / R
= ( 2.4 * 10^3 ) / (2.1 * 10^6 )
= 1.14 * 10^-3 amperes
Answer:
a.) I = 7.8 × 10^-4 A
b.) V(20) = 9.3 × 10^-43 V
Explanation:
Given that the
R1 = 20 kΩ,
R2 = 12 kΩ,
C = 10 µ F, and
ε = 25 V.
R1 and R2 are in series with each other.
Let us first find the equivalent resistance R
R = R1 + R2
R = 20 + 12 = 32 kΩ
At t = 0, V = 25v
From ohms law, V = IR
Make current I the subject of formula
I = V/R
I = 25/32 × 10^3
I = 7.8 × 10^-4 A
b.) The voltage across R1 after a long time can be achieved by using the formula
V(t) = Voe^- (t/RC)
V(t) = 25e^- t/20000 × 10×10^-6
V(t) = 25e^- t/0.2
After a very long time. Let assume t = 20s. Then
V(20) = 25e^- 20/0.2
V(20) = 25e^-100
V(20) = 25 × 3.72 × 10^-44
V(20) = 9.3 × 10^-43 V
Answer:
7,217*10^28 atoms/m^3
Explanation:
- Metal: Vanadium
- Density: 6.1 g/cm^3
- Molecuar weight: 50,9 g/mol
The Avogadro's Number, 6,022*10^23, is the number of atoms in one mole of any substance. To calculate the number of atoms in one cubic meter of vanadium we write:
1m^3*(100^3 cm^3/1 m^3)*(6,1 g/1 cm^3)*(1 mol/50,9g)*(6,022*10^23 atoms/1 mol)=7,217*10^28 atoms
Therefore, for vanadium we have 7,217*10^28 atoms/m^3
