Answer:
Frequency of the wave is f = 50 Hz
Explanation:
It is given that, a wave oscillates 50 times per second. The number of oscillations per second is called frequency of a wave. Mathematically, it can be written as:
Here, number of oscillations, n = 50
So, frequency of this wave is equivalent to 50 Hz. It is equal to number of cycles per second.
So, the correct option is (b). Hence, this is the required solution.
Answer:
4.4345× 10^-7V
Explanation:
The computation of the half voltage for a 1.2T magnetic field applied is shown below
The volume of one mole of copper is
v = m ÷p
= 63.5 ÷ 8.92
= 7.12cm
Now the density of free electrons in copper is
n = Na ÷ V
= 6.02 × 10^23 ÷ 7.12
= 8.456× 10^28/m^3
Now the half voltage is
= IB ÷ nqt
= (5 × 1.20) ÷ (8.456× 10^28 × 1.6 × 10^-19 × 0.1× 10^-2)
= 4.4345× 10^-7V
