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kakasveta [241]
2 years ago
13

A wave oscillates 50 times per second. What is its frequency?

Physics
2 answers:
LenKa [72]2 years ago
8 0

Answer:

Frequency of the wave is f = 50 Hz

Explanation:

It is given that, a wave oscillates 50 times per second. The number of oscillations per second is called frequency of a wave. Mathematically, it can be written as:

frequency=no\ of\ oscillations

Here, number of oscillations, n = 50

So, frequency of this wave is equivalent to 50 Hz. It is equal to number of cycles per second.

So, the correct option is (b). Hence, this is the required solution.

Advocard [28]2 years ago
6 0

"per second" is exactly the definition of "Hertz".

50 per second is 50 Hz. (B)

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Increase in height can cause climber's gravitational potential energy greater than any other mean

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a ship travels a port p and travels 30 km due north. then it changes course and travels 20 km in a direction  30° east of north
liq [111]

When we represent what is given to us on a coordinate plane, we have a figure as shown in the attachment.

To find the distance between P and R, we have to find the Net Displacement of the ship (brown arrow in the figure).

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We see that the first displacement D_{1} = 30 km (blue arrow) is along the y-axis, but the second part of the ship's journey D_{2} = 20 km (red arrow) is at an angle with reference to y-axis.

So, we first find the components of the red arrow along X and Y.

Component of D_{2} along X-axis is given by  D_{2x}  = D_{2} Sin 30 = 10 km

Component of D_{2} along Y-axis is given by  D_{2y}  = D_{2} Cos 30 = 17.32 km

We now add all the vectors along X and along Y separately.

Net Displacement along X  D_{netX} = 10 km

Net Displacement along Y D_{netY} = 30 + 17.32 = 47.32 km

Now that we have the components of the net displacement along X and Y, we make use of Pythagorean Theorem to calculate the D_{net}

D_{net}  = \sqrt{D_{netX} ^{2} + D_{netY} ^{2}}

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Hence, the distance between the ports P and R is 48 km.

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3 years ago
What are the general characteristics of a solid?
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4 0
2 years ago
A bumblebee
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Answer:

given -

initial velocity = 4.09 m/s

acceleration = 1.01 m/s²

distance = 23.4 m

time = ?

using second formula of motion,

s = ut + 1/2 at².

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u = initial velocity

t = time

a = acceleration

23.4 = 4.09(t) + 1/2(1.01)(t) ²

23.4 = 4.09t + 2.02t²

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solving the equation by using quadratic formula

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a = 2.02

b = 4.09

c = -23.4

we get t=2.539 or t= -4.563

time cannot be negative so

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If you wanted to get yellow light , what part of the of the spectrum would the color filter have to absorb ?
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